Answer:
Part a: The probability of breaking even in 6 tosses is 0.3125.
Part b: The probability that one payer wins all the money after the 10th toss is 0.0264.
Explanation:
Part a
P(success)=1/2=0.5
P(Failure)=1/2=0.5
Now for the break-even at the sixth toss
P(Break Even)=P(3 success out of 6)
P(3 success out of 6)
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So the probability of breaking even in 6 tosses is 0.3125.
Part b:
So the probability that one of the player wins all the money after the 10th toss is given as the tenth toss is given as a win so
Wins in 9 tosses is given as 9!/7!=72
The probability that the other person wins
Wins in 8 out of 10 tosses is given as 10!/8!(10-8)!=10!/8!2!=45
So the probability of all the money is won by one of the gambler after the 10th toss is given as
P=number of wins in 9 tosses-Number of wins in 10 tosses/total number of tosses
P=(72-45)/2^16
P=0.0264
So the probability that one payer wins all the money after the 10th toss is 0.0264.
C: electronic fuel injection system control the fuel and air flow automatically during ignition. (In fact the most modern system probably completely ignore throttle input during ignition, at least those that are drive by wire rather than mechanical connections)
Answer:
The correct answer is <em>The site will have all of the company’s applications.</em>
Explanation:
It is the only way to ensure a minimum or zero level of inactivity, because otherwise people will not have the necessary tools to execute their work.
It is hardly obvious that due to the nature of the tasks it is impossible to try to adapt a space that is not adequate to execute them, since the conditions must be the necessary ones to guarantee it.