C=30+15h what is the answers

Professor Ivy has following scores on her final exams: 97 88 66 55 89 72 94 32 84 89 72 76 77 Express answers rounded correctly

Gre4nikov [31]

Answer:

The rest of the question:

Find Mean, Median, Mode, 25th Percentile, 75th Percentile, Maximum, Minimum, Range and IQR.

Let's begin by placing the data points in order from least to greatest:

32 55 66 72 72 76 77 84 88 89 89 94 97

n = 13

1) Mean sometimes called the average = the sum of the data over its number

Mean =( 32+55+66+72+72+76+77+84+88+89+89+94+97 )/13 =

= 991/13 = 76.23 ≈ 76.2 (to the nearest tenth)

2) Median is the middle data point = 77

3) Mode is any number within a set that occurs the most often

Mode = 72 and 89

We will making a data in suitable form to find the remaining requirements:

(32 55 66 72 72 76) 77 (84 88 89 89 94 97)

4) 25th Percentile = Quartile 1 (Q1) which is the median of the first set of data

∴ 25th Percentile = (66+72)/2 = 138/2 = 69

5) 75th Percentile= Quartile 3 (Q3) which is the median of the second set of data

∴ 75th Percentile = (89+89)/2 = 89

6) Maximum = 97

7) Minimum = 32

8) Range = Maximum - Minimum = 97 - 32 = 65

9) IQR (interquartile range) = Q3 - Q1 = 89 - 69 = 20

7 0

4 years ago

43. What is the translation rule to map AHIJ to AH ! J'? 11 H

lutik1710 [3]

Left 4. Or x-4 because the way it moves

3 0

3 years ago

Super Cola is considering a recipe change. There are two recipes under development: a sugary, sweet cola and a less sugary, mild

pickupchik [31]

The researchers should flip a coin to decide independently for each subject, to randomly assign the cola recipe for each subject
Apex :)

8 0

3 years ago

Read 2 more answers

g A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a rando

Tema [17]

Answer:

We accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.

Step-by-step explanation:

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50.

This means that the null hypothesis is:

$H_{0}: \mu = 50$

And the alternate hypothesis is:

$H_{a}: \mu \neq 50$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

50 tested at the null hypothesis:

This means that $\mu = 50$

In a random sample of 36 bins, the sample mean amount was 50.67 pounds and the sample standard deviation was 3.9 pounds.

This means that $n = 36, X = 50.67, \sigma = 3.9$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{50.67 - 50}{\frac{3.9}{\sqrt{36}}}$

$z = 1.03$

p-value:

Since we are testing if the mean is differente from a value and the z-score is positive, the pvalue is 2 multipled by 1 subtracted by the pvalue of z = 1.03.

z = 1.03 has a pvalue of 0.8485

1 - 0.8485 = 0.1515

2*0.1515 = 0.3030

0.3030 > 0.01, which means that we accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.

5 0

3 years ago

Each of 7 students reported the number of movies they saw in the past year. Here is what they reported. 16, 13, 19, 16, 8, 10, 1

svet-max [94.6K]

Answer:

13.1

Step-by-step explanation:

Add all the number together and divide by the number of students (aka total number of responses reported)

16+13+19+16+8+10+10=92

92/7= 13.1428 or about 13.1

8 0

3 years ago

Read 2 more answers