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Sveta_85 [38]
3 years ago
13

Explain how you know the right triangles are similar

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

They have the same angles they are just different scales of each other

Step-by-step explanation:

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Two cars are driving towards an intersection from perpendicular directions. The first car's velocity is 101010 meters per second
guajiro [1.7K]

Answer:

D(L)/dt  = 407,6 m/s

Step-by-step explanation:

Let call A the intersection point.

As the cars are driving from perpendicular directions, they form with a coordinates x and y, a right  triangle, and distance between them is the hypotenuse (L), then

L² = x² + y²

Taking derivatives with respect to time we have:

2*L* D(L)/dt  =  2*x *D(x)/dt  + 2*y* D(y)/dt      (1)

In this equation we know: At a certain time

x  =  444 m       and  D(x)/dt  =  10 m/s

y  =  333 m       and  D(y)/dt  = 666 m/s

And   L = √(x)²  + (y)²    ⇒  L  = √ (444)² +( 333)² ⇒ L = √197136 + 110889

L = √308025

L = 555 m

Thn plugin these values in euatn (1) we get

2* 555 * D(L)/dt (m) =  2* 444* 10 + 2*333*666 (m*m/s)

D(L)/dt  = ( 4440 + 221778)/555  (m/s)

D(L)/dt  = 407,6 m/s

6 0
4 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
HACTEHA [7]

Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(c) The value of P (1 ≤ X ≤ 4) is 0.7154.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defective boards.

The probability that a circuit board is defective is, <em>p</em> = 0.05.

The sample of boards selected is of size, <em>n</em> = 25.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

              =1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

                   =\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

Compute the expected value of <em>X</em> as follows:

E(X)=np=25\times 0.05=1.25

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09

Thus, the expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

8 0
4 years ago
Algebra 1 Prerequisites
frozen [14]
No solution

explanation:
5 0
3 years ago
What is the length of the line segment that is graphed from (3, 1) to (8, 1)?
tia_tia [17]
A.4 units
D.9 units 
id go with 9 units hope this helps
7 0
4 years ago
Read 2 more answers
Here are some of the lowest tempatures recorded in the last 2 centuries for some US cities. Tempatures are in degrees Farhrenhei
oksian1 [2.3K]

Answer:

wouldn't it be A?

Step-by-step explanation:

4 0
3 years ago
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