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Marysya12 [62]
3 years ago
8

The sum of 86,68, and 38 is 192. What do you also know about the sum

Mathematics
1 answer:
Andru [333]3 years ago
8 0
The sum of these numbers is an even number and it is prime. 
Therefore it is not an odd number and is not a composite number.

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I really need help fast and ill do anything just help me plz
podryga [215]
Answer is C. 12.22cm

C = pi x diameter

Diameter = 20cm

You times pi by 20cm (diameter) to get the circumference of approx 62.84cm

Then times the circumference by the angle in the circle

62.84 x 70/360 = 12.22cm

3 0
3 years ago
the telephone company offers two billing plans for local calls. Plan 1 charges $29 per month for unlimited calls and Plan 2 char
kodGreya [7K]

Answer:

Step-by-step explanation:

Plan 2: x= number of months

y= the cost per call

19x + 0.04y

19(4) + 0.04(20)

76 + 0.8

76.8

So the total will be $76.8

4 0
3 years ago
The amount of fat, in grams, in granola is proportional to the volume, in cups, of the granola as shown on the graph.
AlekseyPX
4 cups = 18 g
Divide all by 4 to get 1 cup.
1 cup = 18/4
1 cup = 4.5g
4 0
4 years ago
Read 2 more answers
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
Harry, Peter and 7 girls sit in a row. Harry can't sit in an end seat. In how many ways can they be arranged?
Sonja [21]
All possibilities = 9! 
possibilities that harry sits at an end = 8! + 8! 
possibilities that harry doesn't sit at an end = 9! - 8! -8! 

4 0
3 years ago
Read 2 more answers
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