True. Otherwise we would never stop growing although broken bones regain cartilage into solid bone when we break one but it doesn’t expand.
Answer:
a. People with celiac disease should include foods with dietary fiber such as beans, fruits, vegetables, brown rice, and quinoa.
e. Home-cooked meals are a good way to increase variety and reduce the cost of a gluten-free diet.
Explanation:
Celiac disease is an autoimmune disease, as stated above. This disease causes the defense cells of an organism to attack the stomach cells causing an inflammation that is extended and stimulated by the glutem. As a result, the individual has diarrhea, constipation, weight loss, anemia, a feeling of fullness, colic, abdominal discomfort, severe pain and may even develop ulcers and cancers.
Glutem is a protein found in wheat, barley and rye and for that reason, individuals with this disease should avoid these foods or foods derived from them. This type of diet should accompany the sick person for life and they should be encouraged to eat homemade foods that know the origin and composition. In addition, it is necessary that these people feed on dietary fibers, such as beans, fruits, vegetables, brown rice and quinoa.
Yearly rainfall-12–30 inches; mild summers, cold winters are considered as weather conditions.
<u>Explanation:</u>
To understand the basic difference between the weather condition and climate let’s look into the basic difference. Weather condition is the condition that is been experienced whereas the climate is a condition that is expected to be happening for a long period of time.
Here mild summer and cold winners are the weather condition of that place. Climate will be the average weather of that particular region. While weather is the condition observed during that particular period climate is the condition observed for years together.
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
