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Savatey [412]
3 years ago
10

Poorly trained workers could have an unfavorable effect on which of the following variances? Labor Rate Variance Materials Quant

ity Variance A) Yes Yes B) Yes No C) No Yes D) No No Question 6 options: A) Choice D B) Choice A C) Choice B D) Choice C
Business
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

D) Choice C

Labor Rate Variance - No,  Materials Quantity Variance - Yes

Explanation:

  • Poorly trained workers are one of the main reasons for unfavorable matter as variance as unskilled material, But poorly trained workers are not the reason for unfavorable workers ate variance as the rate is fixed by rules of the industry.
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Gilberto's Performance Pizza is a small restaurant in Philadelphia that sells gluten-free pizzas. Gilberto's very tiny kitchen h
irga5000 [103]

Answer:

In the short run, these workers are <u>variable</u> inputs, and the ovens <u> fixed </u>inputs.

Explanation:

In this matter, we can say that workers are variable inputs, due to the fact that there is a possibility that Gilberto varies the number of workers hired in relation to their production needs. Ovens, on the other hand, can be considered as fixed inputs, which are those inputs, whose quantities cannot be changed in the short term.

4 0
4 years ago
Selected t-accounts of moore company are given below for the just completed year: raw materials bal. 1/1 15,000 credits ? debits
Basile [38]
<span>1. what was the cost of raw materials used in production during the year?
The Cost of Raw Materials Used based on the T-account is 110,000

2. how much of the materials in (1) above consisted of indirect materials?
Of the 110,000 Cost of Raw Materials used, 20,000 consists of indirect materials.
110,000 - 90,000 = 20,000

3. how much of the factory labor cost for the year consisted of indirect labor?
The indirect labor of the factory labor cost for the year is 35,000.
185,000 - 150,000 = 35,000.

4. what was the cost of goods manufactured for the year?
The cost of goods manufactured for the year is 470,000. Work-in-Progress T-account. 

5. what was the unadjusted cost of goods sold for the year?
The unadjusted Cost of goods sold for the year is 450,000. Finished goods T-account. </span>

3 0
4 years ago
Technology has made it possible for software to replace that
Komok [63]

Answer:

Mid-level employees

Explanation:

A p e x

6 0
3 years ago
Fancy Frappucinno purchased a coffee drink machine on January​ 1, 2018​, for $ 39,000. Expected useful life is 10 years or 150,0
Brilliant_brown [7]

Answer:

Straight line depreciation expense:

2018 = $3,000

2019 = $3,000

Unit of activity deprecation expense

2018 = $800

2019= $3,000

Double declining method:

2018 = $7,800

2019 = $6,240

Explanation:

Straight line depreciation method = (Cost of asset - Salvage value) / useful life

($39,000 - $9,000) / 10 = $3,000

The straight line depreciation method allocates the same deprecation expense for each year of the useful life of the machine.

Thus, the depreciation expense in 2018 and 2019 is $3,000

Unit of activity depreciation method = (Total drinks sold in a year / total capacity of the machine ) × Cost of asset - Salvage value)

In 2018, deprecation expense =

(4,000 / 150,000 ) x $30,000 = $800

In 2019, deprecation expense =

(15,000 / 150,000 ) x $30,000 = $3,000

The double declining method =

Depreciation factor × cost of asset

Deprecation factor = 2 × (1/useful life)

2 × (1/10) = 0.2

Deprecation expense in 2018 = 0.2 × 39,000 = $7,800

Net book value = $39,000 - $7,800 = $31,200

Deprecation expense in 2019 = 0.2 × $31,200 = $6,240

I hope my answer helps you

6 0
4 years ago
) A homeowner is considering putting solar panels on the roof of his house. The installed cost of putting 3 kW of solar panels i
mote1985 [20]

Answer:

a) If the homeowner has the $6000 available for the project, what would the cost of electricity from the power company need to be greater than ($/kW-hr) to make the project viable if other investments are providing 8% interest. ($0.0545/kW-hr)

we can use the present value of an annuity formula:

PV = monthly savings x annuity factor

  • PV = $6,000
  • Annuity factor, 300 periods, 0.6667% = 129.52005

monthly savings = $6,000 / 129.52005 = $46.3249

price of kW-hr = $46.3249 / 850 = $0.054499851 ≈ $0.0545

b) If the homeowner had to borrow the $6000 from the bank at 5% interest for 10 years (monthly payments) what would the cost of electricity need to be greater than in $/kWhr from the power company to make the project viable if other investments are providing 8% interest. ($0.0476/kW-hr)

the monthly payment to cover the loan = PV / annuity factor

  • PV = $6,000
  • Annuity factor, 120 periods, 0.4167% = 94.28033

monthly payment = $6,000 / 94.28033 = $63.64

price of kW-hr = $63.64 / 850 = $0.074870588 ≈ $0.0749

4 0
4 years ago
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