Answer:
<h2>let's divide the fig in three quadrilaterals</h2>
(refer attachment)
<u>area </u><u>of </u><u>rectangle</u><u> </u><u>+</u><u>2</u><u>(</u><u>area </u><u>of </u><u>square</u><u>)</u>
<u>1</u><u>)</u><u>area </u><u>of </u><u>rectangle</u><u> </u>
<u>dimensions</u><u>:</u><u>-l=</u><u>1</u><u>0</u><u>m</u>
<u>b=</u><u>6</u><u>m</u>
<h3>
<u>therefore</u><u> </u><u>area </u><u>of </u><u>rectangle=</u><u>length</u><u>×</u><u>b</u><u>r</u><u>e</u><u>a</u><u>d</u><u>t</u><u>h</u></h3>
<u></u>
<u>Area </u><u>of </u><u>2</u><u> </u><u>square</u><u> </u>
<u>2</u><u>×</u><u>3</u><u>×</u><u>3</u>
<u>{</u><u>1</u><u>8</u><u>m</u><u>}</u><u>^</u><u>{</u><u>2</u><u>}</u>
<u>so </u><u>6</u><u>0</u><u> </u><u>+</u><u>1</u><u>8</u><u> </u>
<u>=</u><u> </u><u>{</u><u>7</u><u>8</u><u>m</u><u>}</u><u>^</u><u>{</u><u>2</u><u>}</u>
Answer:
(a-1) *(a^2 +a-1) (a+2)
Step-by-step explanation:
a^4+2a^3-a-2
Lets factor by grouping
a^4-a + 2a^3-2
Factor out an a from the first group and a 2 from the second group
a(a^3 -1) +2(a^3-1)
Factor out (a^3-1)
(a^3-1)(a+2)
We need to recognize that a^3-1 is the difference of cubes
(x^3-y^3) = (x-y) (x^2+xy+y^2)
Let x=a and y=1
(a-1) *(a^2 +a-1) (a+2)
Answer:
Step-by-step explanation:
*photo attached*
Answer:
Hi! I'll do my best to explain for you.
-6(2x-3)+2x =0 First, set the equation equal to zero.
-12x+18+2x=0 Then, distribute the -6 by multiplying it with the -2 and -3.
-10x+18=0 Combine the like terms, which are -12x and 2x, to get -10x.
-10x=-18 You want to get the x on 1 side. Subtract 18 from both sides.
x=-18/-10 Divide by -10 on both sides.
x=1.8 Simplify the fraction. The answer is x=1.8.
I hope this helped!
Answer:
It's the last answer choice.
Step-by-step explanation:
We need to solve for b, so divide each side by H, and then multiply each side by 2 to get rid of the 1/2