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vova2212 [387]
3 years ago
8

Which letter represents the location of -2? *

Mathematics
2 answers:
tester [92]3 years ago
6 0

Answer:

C= -2

Step-by-step explanation:

they count by two's so

A= 6

B= 2

C= -2

D= -6

Sophie [7]3 years ago
5 0

Answer:

C is -2

Step-by-step explanation:

because A its 6

B its 2

C its -2

D -6

hope this helps

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-3p + 8 = -13 <br><br> HELLLLPP
ella [17]

Answer:

p=-7     :)

Step-by-step explanation:

-13-8=3p

-13+(-8)=3p

-21=3p

  ÷3

-7=p

5 0
3 years ago
Find the values of x and y. lines that appear to be tangent are tangent
Ket [755]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of  y  =  122^o

The value of  x = 61^o

Step-by-step explanation:

Generally the total angle that make up a circle is

      \theta _T = 360

From the diagram we see that

    \theta _T  =  y^o + 238^o

=>    y^o  =  360  -238

       y^o  =  122^o

Generally angle that is formed as a result of interception of a chord and a tangent is equal to the intercepted arc divided by 2

 This implies that

           x =  \frac{y}{2}

substituting values

          x =  \frac{122}{2}

          x = 61^o

4 0
3 years ago
9d - 5 = 4d + 35<br> find what d equals.
Debora [2.8K]
9d - 5 = 4d + 35

9d (-4d) - 5 (+5) = 4d (-4d) + 35 (+5)

5d = 40

5d/5 = 40/5

d = 8

hope this helps
3 0
3 years ago
Read 2 more answers
Factor completely 2x2 - 6x - 56.
Gwar [14]

Answer:

your questions is wrong it's 2×2-6x=56

answer= X=-9

Step-by-step explanation:

2×2-6x=56

4-6x=56

-6x=56-4

-6x=54

-X=54/6

-X=9

X=-9

3 0
3 years ago
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

6 0
3 years ago
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