All categories

3 years ago

Which letter represents the location of -2? *

Mathematics

2 answers:

tester [92]3 years ago

6 0

Answer:

C= -2

Step-by-step explanation:

they count by two's so

A= 6

B= 2

C= -2

D= -6

Sophie [7]3 years ago

5 0

Answer:

C is -2

Step-by-step explanation:

because A its 6

B its 2

C its -2

D -6

hope this helps

You might be interested in

What is the answer for this solution?

Stells [14]

Convert to a mixed number:
13/3

Divide 13 by 3:
3 | 1 | 3

3 goes into 13 at most 4 times:
| | 4
3 | 1 | 3
- | 1 | 2
| | 1

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:
| | 4 | (quotient)
3 | 1 | 3 |
- | 1 | 2 |
| | 1 | (remainder)

The quotient of 13/3 is 4 with remainder 1, so:
Answer: 4 1/3

8 0

3 years ago

For the function: f(x) = 21 + 2x − 5x2 Find f(3)

allochka39001 [22]

F(3)=-18

You just replace x for three for your equation and then use Ofer of operations to solve it.

So f(3)= 21+ 2(3)-5(3)^2

The exponent goes first: f(3)= 21+ 2(3)-5(9)

Next is multiplication: f(3)= 21+ 6-45

Now add: f(3)= 27-45

Finally subtract: f(3)= -18

Hope this helps!

6 0

4 years ago

A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were

Rufina [12.5K]

Answer:

a) $ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423$

b) $0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371$

Step-by-step explanation:

1) Data given and notation

n=900 represent the random sample taken

X=372 represent the students were pursuing liberal arts degrees

$\hat p=\frac{372}{900}=0.413$ estimated proportion of students were pursuing liberal arts degrees

$\alpha=0.01$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.