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3 years ago

Change the following to percentages:

Mathematics

1 answer:

ivanzaharov [21]3 years ago

6 0

Answer:

a.83%

b. 48%

c.36%

d.35%

e.69%

f.36%

g.30%

h.69%

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Is 2 (x-y) and 2x-2y equivalent

MArishka [77]

Answer:

yes

Step-by-step explanation:

2(x-y) you distribute the 2 to whats inside the parenthesis

2x-2y

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3 years ago

An open cylinderical tank of radius 70cm contains 385 liters of a liquid find the volume of liquid In a tank

san4es73 [151]

Answer:

5.5

Step-by-step explanation:

385 divided by 70=5.5

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3 years ago

the perimeter of a pentagon (a five-sided polygon) is 50 in. the five sides are represented by consecutive integers. Find the le

posledela

Answer:

8, 9, 10, 11, 12

Step-by-step explanation:

Consecutive integer problems are often easier to work if you consider average values. Here, the middle of the 5 consecutive integers is their average, which is 50/5 = 10.

This tells you the integer side lengths are 8, 9, <em>10</em>, 11, 12.

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3 years ago

What is the answer to -x+y=-5

rosijanka [135]

Is think your answer is x=y+5

Step-by-step explanation:

8 0

4 years ago

The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial

qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

$\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0$

Solve this equation we get

$p(t)=p_0e^{kt}---(1)$

where p is the present population

p₀ is the initial population

If the initial population as doubled in 5 years

that is time t = 5 years

We get

$2p_o=p_oe^{5k}\\\\e^{5k}=2$

Apply In on both side to get

$Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}$

Substitute $k=\frac{In2}{5}$ in $p(t)=p_oe^{kt}$ to get

$\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}$

Given that population of a community is 9000 at 3 years

substitute t = 3 in ${p(t)=p_oe^{\frac{In2}{5}t }}$

$p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8$

<h3>Therefore, the initial population is 5937.8</h3>

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3 years ago