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vladimir2022 [97]

3 years ago

11

Jorgensen Company has sales of $380,000,000, and the break-even point in sales dollars is $323,000,000. Determine Jorgensen Comp

any’s margin of safety as a percent of current sales

1 answer:

nadya68 [22]3 years ago

7 0

Answer:

1) a. break even point in units = fixed cost / contribution margin = 1,750,000 / 5 = 350,000 units

Step-by-step explanation:

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Seventeen more than five times a number is negative twenty three. What is the number?

EastWind [94]

5x+17=-23
Subtract 17 on both sides
5x=-40
Divide by 5 on both sides
X=-8
Double Check:
5(-8)+17=-23
-40+17=-23
-23=-23

6 0

4 years ago

Write an equation for the line parallel to the given line that contains C. <br> C (1,8); 5/7x + 7

Genrish500 [490]

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Answer: $\textsf{y = 5/7x + 51/7}$

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Given: $\textsf{Goes through (1, 8) and is parallel to y = 5/7x + 7}$

Find: $\textsf{Write an equation that follows that criteria}$

Solution: We know that our equation is going to parallel to the line that was given therefore the slope would stay the same at 5/7. We also have a point so we can plug in the values into the point-slope form, distribute, and solve for y.

<u>Plug in the values</u>

$\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}$

$\textsf{y - 8 = 5/7(x - 1)}$

<u>Distribute</u>

$\textsf{y - 8 = (5/7 * x) + (5/7 * (-1))}$

$\textsf{y - 8 = 5/7x - 5/7}$

<u>Add 8 to both sides</u>

$\textsf{y - 8 + 8 = 5/7x - 5/7 + 8}$

$\textsf{y = 5/7x - 5/7 + 8}$

$\textsf{y = 5/7x + 51/7}$

Therefore, the final equation that follows the description that was provided in the problem statement is y = 5/7x + 51/7.

4 0

2 years ago

Explain if the combination of iron and copper sulfate is an example of a chemical reaction

zysi [14]

Answer:

Yes it is.

Step-by-step explanation:

When we mix Fe(iron) to CuSO⁴ (Copper sulphate), Iron removes copper from CuSO⁴ and makes FeSO⁴. This happens because iron is more reactive than copper. We cannot remove iron from this solution now until any stronger element is added.

6 0

3 years ago

Read 2 more answers

_+3=-9 pls help I will give branlyiest <br>

lions [1.4K]

Answer:

-12

Step-by-step explanation:

? + 3 = -9

Subtract 3 from -9

-9 - 3 = -12

? = -12

7 0

3 years ago

Prove that.<br><br>lim Vx (Vx+ 1 - Vx) = 1/2 X>00

faltersainse [42]

Answer:

The idea is to transform the expression by multiplying $(\sqrt{x + 1} - \sqrt{x})$ with its conjugate, $(\sqrt{x + 1} + \sqrt{x})$ .

Step-by-step explanation:

For any real number $a$ and $b$ , $(a + b)\, (a - b) = a^{2} - b^{2}$ .

The factor $(\sqrt{x + 1} - \sqrt{x})$ is irrational. However, when multiplied with its square root conjugate $(\sqrt{x + 1} + \sqrt{x})$ , the product would become rational:

$\begin{aligned} & (\sqrt{x + 1} - \sqrt{x}) \, (\sqrt{x + 1} + \sqrt{x}) \\ &= (\sqrt{x + 1})^{2} -(\sqrt{x})^{2} \\ &= (x + 1) - (x) = 1\end{aligned}$ .

The idea is to multiply $\sqrt{x}\, (\sqrt{x + 1} - \sqrt{x})$ by $\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}$ so as to make it easier to take the limit.

Since $\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} = 1$ , multiplying the expression by this fraction would not change the value of the original expression.

$\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \lim\limits_{x \to \infty} \left[\sqrt{x} \, (\sqrt{x + 1} - \sqrt{x})\cdot \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}\right] \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}\, ((x + 1) - x)}{\sqrt{x + 1} + \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}}\end{aligned}$ .

The order of $x$ in both the numerator and the denominator are now both $(1/2)$ . Hence, dividing both the numerator and the denominator by $x^{(1/2)}$ (same as $\sqrt{x}$ ) would ensure that all but the constant terms would approach $0$ under this limit:

$\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}$ .

By continuity:

$\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \cdots \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1} \\ &= \frac{1}{\sqrt{1 + \lim\limits_{x \to \infty}(1/x)} + 1} \\ &= \frac{1}{1 + 1} \\ &= \frac{1}{2}\end{aligned}$ .

8 0

3 years ago

Read 2 more answers