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3 years ago

_+3=-9 pls help I will give branlyiest

Mathematics

1 answer:

lions [1.4K]3 years ago

7 0

Answer:

-12

Step-by-step explanation:

? + 3 = -9

Subtract 3 from -9

-9 - 3 = -12

? = -12

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Please helppp (750/512)^1/3 what is equivilant to this??

Misha Larkins [42]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------$

$\bf \left( \cfrac{750}{512} \right)^{\frac{1}{3}}\implies \cfrac{750^{\frac{1}{3}}}{512^{\frac{1}{3}}}\implies \cfrac{\sqrt[3]{750^1}}{\sqrt[3]{512^1}}\quad 
\begin{cases}
750=2\cdot 3\cdot 5\cdot 5\cdot 5\\
\qquad 2\cdot 3\cdot 5^3\\
\qquad 6\cdot 5^3\\
512=8\cdot 8\cdot 8\\
\qquad 8^3
\end{cases}
\\\\\\
\cfrac{\sqrt[3]{750}}{\sqrt[3]{512}}\implies \cfrac{\sqrt[3]{6\cdot 5^3}}{\sqrt[3]{8^3}}\implies \cfrac{5\sqrt[3]{6}}{8}$

6 0

3 years ago

Read 2 more answers

Which expressions are equivalent to 3/8(y + 16)

Artyom0805 [142]

Answer:

B,C, and E

Step-by-step explanation:

Multiply the stuff inside by the numbers outside

7 0

3 years ago

Read 2 more answers

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

X3(2x2 + 3x) a. 2x5 + 3x4 b. 5x9 c. 2x6 + 3x3 d. 5x

Serhud [2]

Answer:

$2x^5+3x^4$

Step-by-step explanation:

$x^3\left(2x^2+3x\right)$

Apply distributive law: $a\left(b+c\right)=ab+ac$

$x^3\left(2x^2+3x\right)=x^3\times \:2x^2+x^3\times \:3x$

$x^3\times \:2x^2+x^3\times \:3x$

$2x^5+3x^4$

OAmalOHopeO

5 0

3 years ago

How to solve 4(5x-7)=10x+2

Whitepunk [10]

To solve:
Distribute the 4 to the 5x and –7 by MULTIPLYING.

4(5x)=20x + 4(–7)=–28

20x-28=10x+2 is your new equation.

Subtract 10x from BOTH SIDES to isolate your variable, "x".
20x-10x=10x
10x-10x=0

10x-28=2 is your new equation.

Add 28 to BOTH SIDES to isolate your variable more.
–28+28=0
2+28=30

10x=30 is your new equation.

Finally, DIVIDE both sides by 10 to finish isolating the variable.
10x/10=x
30/10=3

x=3 is your FINAL, SIMPLIFIED answer.

5 0

3 years ago

_+3=-9 pls help I will give branlyiest ​

_+3=-9 pls help I will give branlyiest