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dedylja [7]
2 years ago
8

Given an arithmetic sequence where a1=5 and a9=-19 find a42

Mathematics
2 answers:
kramer2 years ago
6 0

Answer:

-76/8 = -19/2

In an arithmetic sequence, the nth term, an, is given by the formula:

an = a1 + (n - 1)d, where a1 is the first term and d is the common difference.  

So, a9 = a1 + 8d

Substituting in the given data, 12 = 88 + 8d

                                                    -76 = 8d

                                                      d = -76/8 = -19/2

Step-by-step explanation:

i hoped this helped!

wolverine [178]2 years ago
5 0
A1=a=5
a9=a+8d=-19
Since a=5
5+8d=-19
8d=-19-5
8d=-24
d=-24/8
d=-3
a42=a+41d
a42= 5+(41*5)
a42=5+205
a42=210

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Please help me! Need answer quick!
aksik [14]

Let h = height of triangle


h^2 + 12^2 = 15^2


h^2 + 144 = 225


h^2 = 225 - 144



h^2 = 81


sqrt{h^2} = sqrt{81}


h = 9 cm


For part B, we need to find surface area because it represents the perimeter of this 3-D figure. The formula needed is SA = B + LA.


1. First find the lateral area.


LA = perimeter of triangle • height


LA = ph


p = 15 + 15 + 24


p = 30 + 24


p = 54 cm


LA = (54)(9)


LA = 486 cm^2


2. We now find the base of each triangle. This is found by finding the area of each triangle and multiplying by 2.


A = (1/2)bh


A = (1/2)(24)(9)


A = 108 cm^2


A = 2•108 cm^2


A = 216 cm^2 = our B in the surface area formula.


SA = B + LA


SA = 216 cm^2 + 486 cm^2


SA = 702 cm^2


The amount of cardboard needed is 702 cm^2.






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