What is the equation of the line that passes through the point (4,3) and has a slope of 1?
1 answer:
Answer (<u>assuming it can be in point-slope form)</u>:
Step-by-step explanation:
Use the point-slope formula to write the equation of the line. Substitute real values for
,
, and
in the formula.
Since represents the slope, substitute 1 in its place. Since
and
represent the x and y values of a point the line intersects, substitute the x and y values of (4,3) in its place. Substitute 4 for
and 3 for
. This gives the following equation and answer in point-slope form:
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You forgot to mention the graph.
So, I make the graph of both given functions and you will compare your graph with them.
First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
So, I make the graph of both given functions and you will compare your graph with them.
First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.
Answer:
y = -4x + 1
Step-by-step explanation:
The line passes through points (-5,21) and (-4,15)
Slope(m) = change in y ÷ change in x
m =
m = = -36/9 = -4
Taking another point (x,y) on the line and comparing it with point (4,-15):
-4 =
Cross multiplying gives:
y + 15 = -4x + 16
y = -4x + 1