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Varvara68 [4.7K]
3 years ago
13

What is the equation of the line that passes through the point (4,3) and has a slope of 1?

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0

Answer (<u>assuming it can be in point-slope form)</u>:

y-3 = 1(x-4)  

Step-by-step explanation:

Use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line. Substitute real values for m, x_1, and y_1 in the formula.

Since m represents the slope, substitute 1 in its place. Since x_1 and y_1 represent the x and y values of a point the line intersects, substitute the x and y values of (4,3) in its place. Substitute 4 for x_1 and 3 for y_1. This gives the following equation and answer in point-slope form:

y-3 = 1(x-4)

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What are the zeros of the polynomial function f(x)=x(x-4)(x+9)? HELP NEEDED!!!!
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Answer: 0, 4, -9

Set the equation equal to zero.

x(x - 4)(x + 9) = 0

Solve for x by setting each factor equal to zero.

The factors in the equation are x, (x - 4), and (x + 9).

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Step-by-step explanation:

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= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

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<u>2</u>

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