Given: ∠N ≅ ∠S, line ℓ bisects at Q.
1 answer:
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Answer:
<u>The</u><u> </u><u>requ</u><u>ired</u><u> </u><u>num</u><u>ber</u><u> is</u><u> </u><u>7</u><u>0</u><u>.</u>
Step-by-step explanation:
let the no. be 10y + x where x is unit digit and y is ten's digit.
given , sum of the digit is 7
x + y = 7 ...(1)
also , reversing the no. we get 10x + y ,where x is ten's digit and y is unit digit.
given reversed digit decreases the number by 63 .
so, 10y + x - ( 10x + y ) = 63
9y -9x = 63
( dividing both side by 9 )
y - x = 7 ....(2)
adding 1 and 2 [ refer attachment ]
so the required original number is
10y + x = 10×7+0 = 70
1) Taking in account that the function is f(x)= -(2/3) |x+4|-6, I enclose a file with the graph.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.