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3 years ago

Help please i need asap please

Mathematics

1 answer:

Elden [556K]3 years ago

8 0

No
No
No
Yes
Yes
They have to be whole numbers

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What type of relationship does this graph show?

makvit [3.9K]

Answer:

inverse relationship

Step-by-step explanation:

This is inverse becuase as masss increases acceleration decreaes

If this answer was correct plz consider marking brainlist

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3 years ago

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How many x intercept appear on the graph of the polynomial function F(x)=x4-5x2

4vir4ik [10]

$f(x)=x^4-5x^2\\\\x^4-5x^2=0\\\\x^2(x^2-5)=0\\\\x^2[x^2-(\sqrt5)^2]=0\\\\x^2(x-\sqrt5)(x+\sqrt5)=0\iff x=0\ \vee\ x=\sqrt5\ \vee\ x=-\sqrt5$

Answer: 3 x-intercepts.

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3 years ago

Hey, what is 2000x5?

Gnoma [55]

Answer:

Step-by-step explanation:

2000x5=10,000

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3 years ago

WILL GIVE BRAINLIEST IF I CAN AND 40 PTS<br> PLEASE I NEED REAL HELP

Alinara [238K]

Answer:

Step-by-step explanation:I think it's the 2nd one

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3 years ago

What percentage of the semi circle is shaded? <br>

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$

$r \approx 23.606\,\%$

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

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2 years ago