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2 years ago

Find the area of the triangle.

Mathematics

1 answer:

nalin [4]2 years ago

4 0

I believe it is 8x.

Use the formula A=1/2(b*h)

A=1/2(4x(5x-1))
A=1/2(20x-4x)
A=1/2(16x)
A=8x

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Alchen [17]

Answer:

(8,-4)

Step-by-step explanation:

The difference between A and M is 2.5x and -4y

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(8,-4)

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2 years ago

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bixtya [17]

Answer:

$3.14r^2(h-\frac{1}{3}h_1)$

Step-by-step explanation:

Let h be the cylinders height and r the radius.

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$V=\pi r^2h$

-Since the cone is within the cylinder, it has the same radius as the cylinder.

-Let $h_1$ be the height of the cone.

-The area of a cone is calculated as;

$V=\pi r^2 \frac{h}{3}\\\\=\frac{1}{3}\pi r^2h_1$

The volume of the solid section of the cylinder is calculated by subtracting the cone's volume from the cylinders:

$V=V_{cy}-V_{co}\\\\=\pi r^2h-\frac{1}{3}\pi r^2 h_1, \pi=3.14\\\\=3.14r^2(h-\frac{1}{3}h_1)$

Hence, the approximate area of the solid portion is $3.14r^2(h-\frac{1}{3}h_1)$

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3 years ago

a solid sphere is cut into 3 equal wedges. the volume of each wedge is V=4/9π^3. solve the formula for r

algol13

$\\ \qquad\quad\sf{:}\dashrightarrow V=\dfrac{4}{9}πr^3$

It is one third of the solid. sphere

$\\ \qquad\quad\sf{:}\dashrightarrow V_{(Sphere)}$

$\\ \qquad\quad\sf{:}\dashrightarrow 3\left(\dfrac{4}{9}πr^3\right)$

$\\ \qquad\quad\sf{:}\dashrightarrow \dfrac{4}{3}\pi r^3$

Now

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$\\ \qquad\quad\sf{:}\dashrightarrow r^3=\dfrac{3V}{4\pi}$

$\\ \qquad\quad\sf{:}\dashrightarrow r=\sqrt[3]{\dfrac{3V}{4\pi}}$

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