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just olya [345]
3 years ago
10

1. ASA SAS HL SSS AAS 2. PSR = ___

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0
Sas i took that test
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The range of values for the sample mean that fall within 1 standard error of the mean in a sampling distribution is M39 to M43.
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The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

The range of values for the sample mean that fall within 1 standard error of the mean in a sampling distribution is M = 39 to M = 43. What Is the mean of the sampling distribution, and what is the standard error

a) mean = 41, standard error = 2

b) mean = 39 or 43, standard error = 2

c) mean = 41, standard error = 4

e) the mean and standard error are unknowns

Given Information:  

Standard error = 1

Range of values = 39 to 43

Required Information:  

Mean and standard error = ?

Answer:

Mean is 41 and Standard error is 2

Explanation:

We know that the mean and standard error are related as

s = μ + (1)ο

s = μ - (1)ο

43 = μ + (1)ο

39 = μ - (1)ο

option (a) satisfies the above equations

43 = 41 + (1)2

43 = 43

39 = 41 - (1)2

39 = 39

Therefore, the correct option is (a)

Mean is 41 and standard error is 2

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Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu
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Answer:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

Step-by-step explanation:

We have a prortion test.

P₀  =  37 %         P₀  = 0,37

sample size  =  n  =  100

P sample proportion   =   P  = 47 %        P  =  0,47

confidence interval  95 %

α  =   0,05  

One tail-test  (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀      null hypothesis                        P₀  =  0,37

Hₐ  alternative hypothesis                P₀  >  0,37

2.-Confidence interval 95 %

α  =   0,05        and    z(c)  =  1.64

3.-Compute of z(s)

z(s)  =  [  P  -  P₀  ]  /√(P₀Q₀/n) ]  

z(s)  =  [ (  0,47  -  0,37  ) /  √0.37*0,63/100

z(s)  = 0,1 /√0,2331/100     ⇒   z(s)  = 0,1 /0,048

z(s)  = 2.08

4.-Compare  z(s)   and  z(c)

z(s) > z(c)        2.08  > 1.64

5.-Decision:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

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3 years ago
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