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qaws [65]
3 years ago
15

Earning a profit may not be a companies_____ responsibility?

Business
2 answers:
seropon [69]3 years ago
7 0
Earning a profit may not be a companies only responsibility
ikadub [295]3 years ago
4 0
3 - Only - i am correct Trust me
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Xena is a manager at Ex fox Co. She finds two of her subordinates arguing about which format to follow for their power-point pre
Andrew [12]

Answer:

C. The Withdraw Style

Explanation:

The Withdraw or Avoid style is a style that completely evades a conflict. This style is mostly used or appropriate in the following conditions:

  • when the conflict is judged to be trivial, as in the question, Xena sees the issue as a trivial
  • it doesn't require much time to think,
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Other styles include: Accomodating, Collaborating and Competing.

7 0
4 years ago
Difference between information desired and information provided is:_______.
mylen [45]

Answer:

b. measurement error.

Explanation:

Measurement error is defined as the difference in the provided information and the desired information. It is also known as observational error. The value that is measured and the real value that brings out the differences. These errors can emerge and grow rapidly. Random error and systematic error are the two distinct parts of measurement errors.

3 0
3 years ago
You are given the following data concerning​ Freedonia, a legendary​ country: Consumption​ Function: C​ = 100 100 ​+ 0.8 0.8Y ​I
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Explanation:

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3 0
3 years ago
Francesca is making a list of her long-term goals. What advise would you give her?
asambeis [7]
Make them flexible so if you don't want to do it you can change it it would be c. make them flexible
3 0
3 years ago
Read 2 more answers
The probability that a randomly selected education major received a starting salary offer greater than $52,350 is . The probabil
AveGali [126]

Answer:

  • <u>1.  0.0808</u>
  • <u>2. 0.5371</u>
  • <u>3. 58.2%</u>

<u></u>

Explanation:

The first part of the question, with the input data, is missing.

This is missing part:

  • <em>Assume that X, the starting salary offer for education majors, is normally distributed with a mean of $46,292 and a standard deviation of $4,320</em>

<h2>Solution</h2><h2 />

<em>Question 1: The probability that a randomly selected education major received a starting salary offer greater than $52,350 is ________</em>

Find the Z-score.

The Z-score is the standardized value of the random variable and represents the number of standard deviations the value of the random variable is away from the mean:

       Z-score=\dfrac{X-\mu}{\sigma}

      Z-score=\dfrac{\$52,350-\$46,292}{\$4,320}=1.40

      P(X>\$52,350)=P(Z>1.40)=P(Z

The<em> standard normal distribution</em> tables give the cumulative probabilities as the cumulative area under the bell-shaped curve. P(Z>1.40) is the area under the curve that is to the right of Z = 1.40 or, what is the same, P(Z<-1.40) is the area to the left of Z = - 1.40.

Using the former, the table indicates P(Z>1.40) = 0.0808, which is 8.08%

<em>Question 2: The probability that a randomly selected education major received a starting salary offer between $45,000 and $52,350 is _______.</em>

Now you  must find the area under the curve between the two Z-scores.

    Z(X=$45,000)=\dfrac{\$45,000-\$46,292}{\$4,320}=-0.30

   Z(X=$52,350)=\dfrac{\$52,350-\$46,292}{\$4,320}=1.40

Then, you must find the area between Z = -0.30 and Z = 1.40

That is P(Z<1.40) - P(Z < - 0.30) = P(Z > - 1.40) - P(Z < - 0.30)

                                                    = 1 - P(Z< -1.40) - P( Z < -0.30)

Now, you can work with the area under the curve to the left of Z = - 1.40 and to the left of Z = - 0.30.

From the corresponding table, that is: 1 - 0.0808 - 0.3821 = 0.5371

<em></em>

<em>Question 3. What percentage of education majors received a starting offer between $38,500 and $45,000? </em>

<em></em>

For X = $38,500:

      Z=\dfrac{\$38,500-\$46,292}{\$4,320}=-1.80

For X = $45,000

     Z = -0.3 (calculated above)

Then, you must find the area under the curve to the right of Z = - 1.80 and to the left of Z = - 0.3

  • P (Z > - 1.80) - P (Z < - 0.3)
  • 1 - P (Z < - 1.80) - P (Z < - 0.3)
  • 1 - 0.0359 - 0.3821 = 0.582 = 58.2%

5 0
3 years ago
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