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3 years ago

An airplane traveled 700 kilometers in two hours during a trip. What was the average speed of the plane during the trip?

Mathematics

1 answer:

Igoryamba3 years ago

8 0

9514 1404 393

Answer:

350 km/h

Step-by-step explanation:

Speed = distance/time

speed = (700 km)/(2 h) = 350 km/h

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An athlete buys a baseball bat and pays a fee for each baseball lesson taken. The fee for each lesson is the same. The number of

jolli1 [7]

Answer:

The cost of the lessons taken

Step-by-step explanation:

Let

y -----> the total paid for the baseball bat and the lessons

c ----> the number of lessons

we have

y=25c+75

This is a linear equation in slope intercept form

y=mx+b

where

b=$75 -----> the price of he baseball bat (y-intercept)

m=25 $/lesson ----> the slope of the linear equation

therefore

25c represent the cost of the lessons taken

7 0

3 years ago

Ben can type 25 words in half a minute. At this rate, how many words can he type in 5 minutes?

Kruka [31]

I can’t see the “students work”. But the answer would be 250 words in 5 minutes.
Here’s how you would set up the equation:
25x(5*2)=
So your first step would be to multiply 5 and two because they’re in parenthesis, which would be 10.
So now you have:
25x10
25 times 10 is 250.
Hope that makes sense and helps! :)

4 0

3 years ago

You want to test your newly created Web site, so you have 250 people access it from random locations at random times. Of the peo

Arte-miy333 [17]

Answer: 505

Step-by-step explanation:

The formula to find the sample size n , if the prior estimate of the population proportion (p) is known:

$n= p(1-p)(\dfrac{z}{E})^2$ , where E= margin of error and z = Critical z-value.

Let p be the population proportion of crashes.

Prior sample size = 250

No. of people experience computer crashes = 75

Prior proportion of crashes $p=\dfrac{75}{250}=0.3$

E= 0.04

From z-table , the z-value corresponding to 95% confidence interval = z=1.96

Required sample size will be :

$n=0.3(1-0.3)(\dfrac{1.96}{0.04})^2$ (Substitute all the values in the above formula)

$n= (0.21)(49)^2= 0.21\times2401$

$n= 504.21\approx505$ (Rounded to the next integer.)

∴ Required sample size = 505

6 0

3 years ago

PLEASE HELP ME AND BE CORRECT BEFORE ANSWERING

ddd [48]

Answer:

8 units left , 5 units up

Step-by-step explanation:

4 0

3 years ago

Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p repre

Anastasy [175]

Answer:

Solving steps:

Question: Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.

Find: How much money did Sam have in his pocket?.

Solution: Let the equation be

p represent amount of money

p represent amount of moneyt represent total

p represent amount of moneyt represent totalf represent money found

insert the values

add 19.75 from 6.50

THEREFORE THE AMOUNT OF MONEY SAM HAVE IN HIS POCKET IS ABOUT $26.25

8 0

2 years ago