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Ostrovityanka [42]
3 years ago
15

An airplane traveled 700 kilometers in two hours during a trip. What was the average speed of the plane during the trip?

Mathematics
1 answer:
Igoryamba3 years ago
8 0

9514 1404 393

Answer:

  350 km/h

Step-by-step explanation:

Speed = distance/time

speed = (700 km)/(2 h) = 350 km/h

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What is the equation 22-2h=-5?
Marrrta [24]

Answer:

h = -9

Step-by-step explanation:

Simplifying

5h + 22 + -2h = -5

Reorder the terms:

22 + 5h + -2h = -5

Combine like terms: 5h + -2h = 3h

22 + 3h = -5

Solving

22 + 3h = -5

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-22' to each side of the equation.

22 + -22 + 3h = -5 + -22

Combine like terms: 22 + -22 = 0

0 + 3h = -5 + -22

3h = -5 + -22

Combine like terms: -5 + -22 = -27

3h = -27

Divide each side by '3'.

h = -9

Simplifying

h = -9

4 0
3 years ago
Name the property illustrated.<br><br> 1 + 4 = 4 + 1
aleksley [76]

Answer: Communitive property of addition

Step-by-step explanation:

The communitive property states that if you reverse the order of a multiplication or addition problem you will get the same result.

communitive property examples

x + 2 = 2 + x

xy = yx

4 0
2 years ago
According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
Ann [662]

Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

4 0
2 years ago
PLEASE HELP! NEED TO SUBMIT SOON! NOT SURE IF I GOT THE RIGHT ANSWERS! THANK YOU IN ADVANCE!!!
Eddi Din [679]
Nice

4s=amount of grams of protine in straberry for s ounces
3b=amount of grams of protine in banana for b ouces

total ounces is 6
s+b=6

total grams is 22
4s+3b=22

s+b=6
4s+3b=22
those are the 2 equations

a.
s+b=6
4s+3b=22


b. elmination, we can elminate alll the b's and have 1s left

c.
multiply first equaiton by -3 and add to second

4s+3b=22
<u>-3s-3b=-18 +</u>
1s+0b=4
s=4
sub
s+b=6
4+b=6
minus 4
b=2

4 oz straberry
2 oz banana
8 0
3 years ago
WILL MARK BRAINLIEST HELP ASAP ASAP
Mrac [35]

Answer:

not possible

Step-by-step explanation:

8 0
3 years ago
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