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9966 [12]
3 years ago
11

Please help dont answer if you dont know

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0
It is 30 because circumference is 3xdiameter
Diameter is 2x5=10
10x3=30
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Please Help!!! I NEED THIS ASAP
Oksi-84 [34.3K]

person is si mis iosnmasabgoiuwgaufgafuawf

4 0
3 years ago
Brooke and Lamont ran a half marathon. Brooke finished in 1 hour 40
Paha777 [63]

Answer:

B. Brook finished in 100 minutes, so Lamont was faster.

Step-by-step explanation:

1 hour = 60 Minutes

60 minutes + 40 minutes = 100 Minutes.

If you run and you have more minutes then someone else that means you ran for a longer time and your a little bit slower?

Comment down below, Did I help? ^w^

6 0
3 years ago
(3x3 - 7x2 + 12) - (3x3 + 6x2 + 10x)
inn [45]
(3x³ - 7x² + 12) - (3x³ + 6x² + 10x)
(3x³ - 3x³) + (-7x² + 6x²) - 10x + 12
-x² - 10x + 12
6 0
3 years ago
Read 2 more answers
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
What are the vertical asymptote(s) of y= (x-6)/(x+8) (x-7)
White raven [17]

Answer:

x = -8 and x= 7

Step-by-step explanation:

recall that for a rational expression, the vertical asymptotes occur at x-values that causes the expression to become undefined. These occur when the denominator becomes zero.

Hence the asymptototes will occur in x-locations where the denominator , i.e

(x+8)(x-7) = 0

solving this, we get

(x+8) = 0 ----> x = -8

or

(x-7) = 0 ------> x = 7

hence the asymptotes occur x = -8 and x= 7

5 0
3 years ago
Read 2 more answers
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