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3 years ago

9

I am confused with this

1 answer:

Aleksandr-060686 [28]3 years ago

8 0

Answer:

Answer is A) HL

Step-by-step explanation:

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find the width of radius r if the width w of the shaded region is 2cm and its area is 176cm^2, use 22/7 for pi (its a full circl

arsen [322]

The area of a shape is the amount of space it can occupy.

<em>The value of r is 13</em>

From the question (see attachment), we have:

$\mathbf{A =176}$ --- area of the shaded region

$\mathbf{w = 2}$ --- the width of the shaded region

The area of the complete circle would be:

$\mathbf{A_1 =\pi (r + w)^2}$

The area of the small circle is:

$\mathbf{A_2 =\pi r^2}$

So, the area of the shaded region is:

$\mathbf{A = A_1 - A_2}$

Substitute known values

$\mathbf{176 =\pi (r + w)^2 - \pi r^2 }$

Substitute 2 for w

$\mathbf{176 =\pi (r + 2)^2 - \pi r^2 }$

Expand

$\mathbf{176 =\pi (r^2 + 4r + 4) - \pi r^2 }$

Open brackets

$\mathbf{176 =\pi r^2 + 4\pi r + 4\pi - \pi r^2 }$

Cancel out line terms

$\mathbf{176 =4\pi r + 4\pi }$

Divide through by 4

$\mathbf{44 =\pi r + \pi }$

Factor out pi

$\mathbf{44 =\pi(r+ 1) }$

Divide through by pi

$\mathbf{r + 1= \frac{44}{ \pi} }$

Substitute 22/7 for pi

$\mathbf{r + 1= \frac{44}{ 22/7} }$

Using a calculator, we have

$\mathbf{r + 1= 14}$

Solve for r

$\mathbf{r= 14 -1}$

$\mathbf{r= 13}$

Hence, the value of r is 13

Read more about areas of circles at:

brainly.com/question/23328170

6 0

1 year ago

Brooke earns $7 an hour at her job now. She can represent the total she makes in a week using the expression 7r. Brooke has aske

alexandr402 [8]

A. 8r would be the correct answer

4 0

2 years ago

Read 2 more answers

If f(x)= sqrtx-3 and g(x)=1-x^2, then what do you notice about the domain of (fxg)(x)?

Oduvanchick [21]

Answer:

$x\geq0$ if $f(x)=\sqrt{x}-3$

$x\geq3$ if $f(x)=\sqrt{x-3}$

Step-by-step explanation:

If $f(x)=\sqrt{x}-3$ then the domain of f(x) is all positive real numbers. This is $x\geq0$

On the other hand the domain of g(x) would be all real numbers because it is a polynomial function

Therefore

$(f*g)(x) = f(x)*g(x)\\\\(f*g)(x) =(\sqrt{x}-3)*(1-x^2)$

$(f*g)(x) =\sqrt{x}-x^2(\sqrt{x})-3+3x^2$

Then the domain of $f(x) *g(x)$ will be the same domain of $f(x)$

All positive real numbers, $x\geq0$ or x ∈ [0, ∞)

-----------------------------------------------------------------------------------------------

If f(x) = $\sqrt{x-3}$ then the domain of f(x) is

$x-3\geq0\\\\x\geq3$

Therefore

$(f*g)(x) = f(x)*g(x)\\\\(f*g)(x) =(\sqrt{x-3})*(1-x^2)$

$(f*g)(x) =\sqrt{x-3}-x^2(\sqrt{x-3})$

Then the domain of $f(x) *g(x)$ will be the same domain of $f(x)$

$x\geq3$ or x ∈ [3, ∞)

3 0

2 years ago

Read 2 more answers

In which set(s) of numbers would you find the number

kykrilka [37]

Answer:

I think the ans is real number

3 0

2 years ago

This question is asking for a response so please give me at least 2 sentences thank youuuu

Scorpion4ik [409]

I=5+10h
i=75
75=5+10h
-5 both sides
70=10h
÷10 both sides
h=7
With the information given, we can conclude Anthony worked on Steve's bike for 7 hours.
We know this, if we set 75 equal to the formula given and solve for h.

3 0

2 years ago