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Vilka [71]
3 years ago
6

Which graph represents the function -2x - 5y = -10? Please explain!!

Mathematics
2 answers:
damaskus [11]3 years ago
6 0
The answer would be J because if the equation was transferred into a positive then it would be 2y and 5x marking 5x on the bottom and 2y vertically.
Hope this helps!!
BigorU [14]3 years ago
4 0

Answer:

Graph J represents the function -2x-5y=-10

Step-by-step explanation

To find the answer you have to find the y and x-intercepts first. To find the x and y-intercept I came up with two equations; -5y=-10 and -2x=-10. I came up with these equations because I'm finding the intercepts, so I know I have to substitute x and y with 0 one at a time. To solve the first equation I just divided -5 from both sides and got y=2, so my first intercept is (0, 2). I solved the second equation by dividing -2 from both sides and got x=5 which means my second intercept is (5, 0). Now I graph the two points on a graph and connect the dots, which turns out to be graph J on your image.

Hoped this helped you : )

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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
3 years ago
Plz hurry will mark brainiest
aliya0001 [1]

Answer:

B. 4

Step-by-step explanation:

The sign \geq means greater than or equal to

The sign > just means greater than

4 is a solution for x \geq4, because 4 is equal to 4, but not a solution for x>4, because 4 is not greater than 4

Hope this helps! :)

6 0
3 years ago
Jack's house is located at the origin (0,0). He walks 2 blocks right. Then, he walks 6 blocks up. Finally, he walks 3 blocks rig
attashe74 [19]

Answer: 5, 6

Step-by-step explanation:

0 + 2 = 2

2 , 0

0 + 6 = 6

2, 6

2 + 3 = 5

5, 6

5 0
3 years ago
Which are perfect squares? Check all that apply.
den301095 [7]
36, 16, 81, and 64 are all of your perfect squares.

If you need me to explain, just let me know! :)
6 0
4 years ago
Read 2 more answers
a tin mine is estimated to have tin reserves worth two million ringgit. if the monthly extraction is 5% of the value of the rese
andrew-mc [135]
Month_1 Value = Month_0 Value * 0.95

Month_2 Value = Month_1 Value * 0.95 = Moth_0 Value * 0.95*0.95 = Month_0 Value * 0.95^2

Month _n Value = Month_0 Value * (0.95)^n

After 2 years ==> n = 24

Month_24 Value = Month_0 Value * (0.95)^24 = 2,000,000 *(0.95)^24 = 583,978.05
6 0
3 years ago
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