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2 years ago

Please help me quickly, timed test:(

Mathematics

2 answers:

Dennis_Churaev [7]2 years ago

7 0

Answer:

1 & 7

Step-by-step explanation:

I guessed. Good Luck!

masya89 [10]2 years ago

6 0

Answer:

Angles 1 and 5

Step-by-step explanation:

Corresponding angles: Angles that are in the "same place" from the transversal.

So, angles 1 and 5 are in the same spots, because they are both the top left of the transversal.

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Karo-lina-s [1.5K]

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2 years ago

The equation of circle C is (x-8)^2+(y+3)^2=49. Find the center and radius of circle C.

Dominik [7]

C is the best option and compare it with the equation of circle to get values

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2 years ago

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1 . Evaluate 3a - 12 divided by a for a =4 2. Evaluate 3x- 2y , if x= 5 and y =3

ziro4ka [17]

This is how I understood the question

Hope I helped!

3 0

2 years ago

In a right triangle whose area is 12, each leg is as long as the side of a certain square. What is the area of the square?

kakasveta [241]

The area of a Square is 144 because 12x12 is 144 and if both sides are 12 then that equals 144.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

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2 years ago

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Please help me quickly, timed test:(​

Please help me quickly, timed test:(