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zhuklara [117]
3 years ago
14

Why do I miss her? :/

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

because you probably liked her or you just miss her company ya know talking with her or just messing around lol

You might be interested in
What’s the answer I just need a quick answer and my teacher thinks I’m wrong
Goryan [66]

Answer:

58.5

Step-by-step explanation:

9 x 13 = 117

117 divided by 2 = 58.5

3 0
2 years ago
Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621​
REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

a=-6

T_n=58

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

\therefore d=a_2-a_1=-5-(-6)=-5+6=1

Now we use the formula of A.P.

T_n=a+(n-1)d

On substituting the values, we get;

58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65

So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

Now we use the formula of Sum of n_terms.

S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0
3 years ago
What is the measure of angle x?<br> Enter your answer in the box.<br> mZx = 37 82
ikadub [295]

Answer:61

Step-by-step explanation:

Its common logic

5 0
3 years ago
A soccer player uses her head to hit a ball up in the air from a height of 2 meters with an initial vertical velocity of 5 meter
Mandarinka [93]

Answer:1.32 s

Step-by-step explanation:

Given

The initial height of ball H=2 m

Initial velocity u=5 m/s

Height of ball at any instant is given by

H=-4.9t^2+5t+2

The ball will hit the ground when h=0

-4.9t^2+5t+2=0\\4.9t^2-5t-2=0\\t=\dfrac{5\pm\sqrt{25+4(4.9)(2)}}{2\times 4.9}\\t=\dfrac{5\pm\sqrt{64.2}}{9.8}\\t=\dfrac{5+8.01}{9.8}=1.32\ s\quad\text{Neglecting negative value of t}

3 0
2 years ago
a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and
fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

x(t) = -4.9t^{2} + 9.8t

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format x(t) = at^{2} + bt + c

The vertex is the point (t_{v}, x(t_{v})), in which

t_{v} = -\frac{b}{2a}

In this question:

x(t) = -4.9t^{2} + 9.8t

So a = -4.9, b = 9.8

Vertex:

t_{v} = -\frac{9.8}{2*(-4.9)} = 1

The time taken for the upward motion is 1 second.

x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

-4.9t^{2} + 9.8t = 0

4.9t^{2} - 9.8t = 0

4.9t(t - 2) = 0

4.9t = 0

t = 0

Or

t - 2 = 0

t = 2

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

5 0
2 years ago
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