The length of the rectangle is 10 cm and perimeter of the rectangle is 32 cm.
Step-by-step explanation:
Given,
The area of rectangle = 60 sq cm
Width (b) of the rectangle = 6 cm
To find the length and perimeter of the rectangle.
Formula
The area of the rectangle = l×b
The perimeter of the rectangle = 2(l+b)
According to the problem,
l×b = 60
or, l×6 = 60
or, l = 60÷6 = 10
Length (l) = 10 cm
Perimeter = 2×(10+6) cm = 32 cm
<em><u>The equivalent expressions are:</u></em>
<em><u>Solution:</u></em>
<em><u>Given expression is:</u></em>
We have to find the equivalent expressions
By distributive property,
a(b + c) = ab + ac
Therefore,
Thus equivalent expressions are found
Solve first for the solution of the inequalities. This can be done by replacing first the inequalities sign with the equal sign.
x + y = 1
2y = x - 4
The values of x and y from the system of linear equation are 2 and -1. This means that the intersection of the lines should be at point (2, -1).
Substitute 3 to x and determine the value of y from the second inequality.
2y ≥ x - 4
Substituting,
2y ≥ 3 - 4, y ≥ -1/2
Hence, the solution to this item should be the fourth one.
Answer:
See below ~
Step-by-step explanation:
Given :
⇒ m∠1 = m∠2
⇒ HD = GF
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To Prove :
<u>Δ EHD ≅ Δ EGF</u>
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Solving :
⇒ m∠1 = m∠2 (Given)
⇒ HD = GF (Given)
⇒ ∠E = ∠E (Common angle)
⇒ ΔEHD ≅ ΔEGF (AAS congruence)
