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Shkiper50 [21]
3 years ago
5

What's the area please

Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answer:

its area is square (11+17+4)

I guess this may help you

Marina CMI [18]3 years ago
3 0

Answer:

222

Step-by-step explanation:

11* 17 = 187

4*5=20

5*6/2=15

187+20+15=222

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5c-1÷4=4+10c÷9 is there a solution or no solution and if there is I would like to see the steps in solving this equation so I ca
vekshin1

I don’t think this will help exactly but I hope it does x

6 0
3 years ago
In an isosceles triangle the length of the base is 10 cm
lawyer [7]

The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.

<h3>How to calculate the radius?</h3>

From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.

Let A = area of the triangle

Let S = semi perimeter of the triangle.

The radius will be: = A/S

where,

S = \dfrac{(a + b + c)}{2} = \dfrac{(13 + 13 + 10)}{2} = 18

The radius will be:

 =\dfrac{(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{10})} { 18}

= 3.33cm

In conclusion, the radius is 3.33cm.

Learn more about triangles on:

brainly.com/question/17335144

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5 0
2 years ago
What is the solution to question number 33?
Oksana_A [137]
If the width of the garden is w, then the maximum area available is a square, giving you w² as the dimensions. So:
w²=-w²+28w
2w²=28w
w=14
The perimeter is 14 x 4, or 56 feet
How many seed packets??? No idea
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7 0
3 years ago
Can someone solve this? Number 25 only please.
V125BC [204]
0.06x0.06 = 0.0036 

dont wory about the zeros just the actual numbers than add the zeros
6 0
3 years ago
Suppose that 75% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
RSB [31]

Answer:

b) 0.2961

c) 0.2251

d) Mean = 11.25, Standard deviation =  1.667  

Step-by-step explanation:

We are given the following information:

We treat trucks undergoing a brake inspection passin as a success.

P( trucks undergoing a brake inspection passes the test) = 75% = 0.75

a) Conditions for binomial probability distribution

  1. There are n independent trial.
  2. Each trial have a success probability p
  3. The probability of success is same for all trials.

Then the number of trucks undergoing a brake inspection follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

b) P(proportion of groups will between 8 and 10 trucks pass the inspection)

We have to evaluate:

P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961

c) P( exactly 3 trucks fail the inspection)

p = 0.25

P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251

d) Mean and standard deviation

\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667

6 0
3 years ago
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