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yulyashka [42]
3 years ago
11

The width of a laptop is 11.25 inches. The width is 0.75 times the length. What is the length of the laptop?

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

8.4375 is the correct answer

Marat540 [252]3 years ago
5 0
8.4375 is the correct answer
You might be interested in
(01.05 MC)
Dennis_Churaev [7]

Answer:

least to greatest : 14/9 , sqrt 7, sqrt 13, sqrt 40, 4^3

Step-by-step explanation:

7 0
3 years ago
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
Which statement is correctly written as a conditional statement?
bekas [8.4K]

The statement that correctly written as a conditional statement is; A number, such as 10, is a composite number because it is even. so the correct option is D.

<h3>What are natural numbers, rational numbers, integers and irrational numbers?</h3>

Natural numbers are: 1, 2, 3, ....

Integer numbers are: ...., -2, -1, 0, 1, 2, ... (so it includes positive and negative natural number, and 0 )

Rational numbers are numbers which can be written in the form of a/b  

where a and b are integers.

Irrational numbers are those real numbers which are not rational numbers.

Here, Know that all natural numbers are integers, all integers are rational numbers. That means, natural numbers are not irrational.

A composite number is a number divisible by another number than 1 and the number itself.

To find example, a sum of two composite numbers, which is not a composite number, is needed.

The statement that correctly written as a conditional statement is; A number, such as 10, is a composite number because it is even.

Hence so the correct option is D.

Learn more about composite number;

brainly.com/question/19312484

#SPJ1

3 0
2 years ago
HELPPPPPPPPPPPPPPPPPP
Finger [1]

Answer:

Given expression : \frac{9}{4}-2(4x+\frac{4}{3} )+\frac{5}{2}x    ......[1]

Using distributive property:  a\cdot (b+c) =a\cdot b + a\cdot c

[1]⇒   \frac{9}{4} - 2(4x) - 2(\frac{4}{3})+\frac{5}{2} x

Simplify:

\frac{9}{4} - 8x - \frac{8}{3}+\frac{5}{2}x

Like terms are those terms which are same variables.

Combine like terms: we get;

(\frac{9}{4} - \frac{8}{3}) - 8x + \frac{5}{2}x            ......[2]

\frac{27-32}{12} -8x +\frac{5}{2} x

Simplify:

\frac{-5}{12} -8x +\frac{5}{2}x  

or

\frac{-5}{12} - \frac{11}{2}x  

we can write equation [2] as;

\frac{27}{12} - \frac{8}{3} - 8x + \frac{5}{2}x

Combine like terms of x variables;

\frac{27}{12} - \frac{8}{3} - \frac{11}{2}x

Therefore, the expressions which are equivalent to the Given expression are:

\frac{9}{4} - 2(4x) - 2(\frac{4}{3})+\frac{5}{2} x

\frac{-5}{12} -8x +\frac{5}{2}x  

\frac{27}{12} - \frac{8}{3} - \frac{11}{2}x

\frac{-11}{2}x - \frac{5}{2}





3 0
3 years ago
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