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3 years ago

Date

Mathematics

2 answers:

Maslowich3 years ago

7 0

Answer:

Fri, Feb, 8th, at 3:16 pm.

Step-by-step explanation:

Pretty sure bout it!! :)

ALSO, I JUST TOOK THE TEST AND I GOT A 100%.

EDIT: I just now saw the other persons answer, and no i DID NOT copy them, so don't even say I did, cuz you're not me and you don't know what i think.... :-)

Yakvenalex [24]3 years ago

5 0

Answer:

Friday, Feb. 8, at 3:16 p.m.

Step-by-step explanation:Just took it :3

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01.01 LC)Which number line best shows how to solve −2 − ( −6)?

liraira [26]

Answer:

-6 - (-8) = 2.

Your number line might have a bubble at 2. Or it may show movement 8 units to the right of -6. Whatever it is, you should end up at the value of 2.

Step-by-step explanation:

4 0

3 years ago

Neeeeed helpppppp please

MissTica

Answer:

Scale factor = 7

Step-by-step explanation:

Dilation with scale factor to map HEFG to DABC will be,

Scale factor = $\frac{\text{Dimension of Image DABC}}{\text{Dimension of preimage HEFG}}$

= $\frac{\text{Length of CD}}{\text{Length of GH}}$

Length of CD = Distance between two points C(0, -7) and D(-7, 0)

= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(-7-0)^2+(0+7)^2}$

= $\sqrt{98}$

= $7\sqrt{2}$

Length of GH = Distance between G(0, -1) and H(-1, 0)

= $\sqrt{(-1-0)^2+(0+1)^2}$

= $\sqrt{2}$

Scale factor = $\frac{7\sqrt{2} }{\sqrt{2} }$

= 7

6 0

3 years ago

Sarah had 730 m of lace to decorate some dresses. She used 4 m of lace to decorate each dress and had 510 m of lace left. Then,

pashok25 [27]

Answer:
$5830.

Explanation:
730-510=220m
220/4=55 dresses made
55*106=$5830

6 0

2 years ago

Draw the dilation of ABCD with center D and scale factor. Label the dilation (JKL.

Ad libitum [116K]

I can’t put pictures

5 0

3 years ago

Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms

Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 , r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x) → θ₁ = tan⁻¹ (4/3)= 0.927 rad , θ₂ = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0

3 years ago