The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
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Answer:
the answer for this question is 1000times.
Step-by-step explanation:
the value for 9 in 157,900 is nine hundred(900).and the value of 9 in 901,532 is nine hundred thousand(900000).
900×1000= 900,000.
Answer:
table 1
Step-by-step explanation:
table one, because you have different value of x (inputs) with no repetition for the same value
8/1 x 2/3 = 16/3. 16/3 = 5 1/3
Ok i hope this helps and if it does pls give me brainliest!
So the longest line is 8 and makes a 90 degree angle with another smaller line which is labled 3.6. X is longer than 3.6 ( only by a little bit) But it looks like its half of the longest line (8). So i think the answer would be X equals 4. But i was thinking about it more i relized that you would prob just divide 8 by 3.6 which would be 2.22222 .... And that rounded tot he nearest 10th would be 2.2.
