She has been with her book club for eight months.
Answer:
57,000 grams
Step-by-step explanation:
Answer:
I believe it is c
Step-by-step explanation:
Correct me if I'm wrong but since the two lines look the same length I believe it is c
Evaluate the function
g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.
This is tedious math work but necessary to sharpen your skills.
Let x = -2
g(-2) = 2(-2)^2 + 3(-2) – 5
g(-2) = 2(4) - 6 - 5
g(-2) = 8 - 11
g(-2) = -3
Now let x = 0 and repeat the process.
g(0) = 2(0)^2 + 3(0) - 5
g(0) = 0 + 0 - 5
g(0) = -5
Lastly, let x = 3.
g(3) = 2(3)^2 + 3(3) - 5
g(3) = 2(9) + 9 - 5
g(3) = 18 + 9 - 5
g(3) = 27 - 5
g(3) = 22
Did you follow through each step?

<em>-------------------------------------------------------------</em>

<u>It's 10.</u>
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
<u>It's 90</u>