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3241004551 [841]

2 years ago

10

Joseph drove from Kentucky to Louisiana. It took 35 gallons of gas for him to get there. Gas costs $2.09 per gallon. How much mo

ney did Joseph spend on gas?

1 answer:

77julia77 [94]2 years ago

4 0

$ 73.15
35 gallons x $2.09 per gallon = $73.15 for 35 gallons

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What is the value of the expression 1/2(12.g)-h when g=1/4 and h=1/2

Gelneren [198K]

Answer:

1

Step-by-step explanation:

1/2(12.1/4)-1/2

1/2(3)-1/2

1.5-0.5

1

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2 years ago

The volume of a rectangular prism (shown below) is 48x^3+56x^2+16x Answer the following questions:

pickupchik [31]

Answer:

(a)

$Length = 8x\\Width = 3x + 2\\Height = 2x + 1$

(b)

$P(2) = 640$

(c)

$Length= 16$

$Width = 8$

$Height =5$

(d)

$Volume = 640$

Step-by-step explanation:

Given

$P(x) = 48x^3 + 56x^2 + 16x$

Solving (a): The prism dimension

We have:

$P(x) = 48x^3 + 56x^2 + 16x$

Factor out 8x

$P(x) = 8x(6x^2 + 7x + 2)$

Expand 7x

$P(x) = 8x(6x^2 + 4x + 3x + 2)$

Factorize

$P(x) = 8x(2x(3x + 2) +1( 3x + 2))$

Factor out 3x + 2

$P(x) = 8x(3x + 2)(2x + 1)$

So, the dimensions are:

$Length = 8x\\Width = 3x + 2\\Height = 2x + 1$

Solving (b): The volume when $x = 2$

We have:

$P(x) = 48x^3 + 56x^2 + 16x$

$P(2) = 48 * 2^3 + 56 * 2^2 + 16 * 2$

$P(2) = 640$

Solving (c): The dimensions when $x = 2$

We have:

$Length = 8x\\Width = 3x + 2\\Height = 2x + 1$

Substitute 2 for x

$Length=8*2$

$Length= 16$

$Width = 3*2+2$

$Width = 8$

$Height = 2*2 + 1$

$Height =5$

So, we have:

$Length= 16$

$Width = 8$

$Height =5$

Solving (d), the volume in (c)

We have:

$Volume = Length * Width * Height$

$Volume = 16 * 8 * 5$

$Volume = 640$

8 0

2 years ago

The EPA wants to know the daily level of pollutant discharge in the manufacturing district in Pittsburgh for February 2005. The

dangina [55]

Answer:

The 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).

Step-by-step explanation:

Let <em>X</em> represent the daily level of pollutant discharge in the manufacturing district in Pittsburgh.

The monitoring equipment reveals that for the 28 days of the February month

Mean daily discharge per factory, ( $\bar x$ ) = 30.2 tons

Standard deviation daily discharge per factory, (<em>s</em>) = 9.1 tons

Compute the critical value of <em>t</em> for 95% level of confidence and (n - 1 =) 27 degrees of freedom as follows:

$t_{0.05/2, 27}=2.052$

*Use a t-table.

Compute the 95% confidence interval for the true population mean of pollutant discharge as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\frac{s}{\sqrt{n}}$

$=30.2\pm 2.052\times\frac{9.1}{\sqrt{28}}\\\\=30.2\pm 3.53\\\\=(26.67, 33.73)\\\\\approx (26.7, 33.7)$

Thus, the 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).

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blondinia [14]

Answer:?

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