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timurjin [86]
4 years ago
13

Which expression is arranged by decreasing powers of x for the given polynomial? 2x^2- 4x^4+3+6x

Mathematics
1 answer:
Fudgin [204]4 years ago
5 0

Answer:

-4x^4+2x^2+6x+3 is the required decreasing order expression

Step-by-step explanation:

We have been given a polynomial:

2x^2-4x^4+6x+3

The decreasing power means from highest power to the lowest power.

Highest power is 4 then 2 then 1 and then constant so, we will start from 4 an ends at constant.

-4x^4+2x^2+6x+3 is the required decreasing order expression.

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I need help what's my equation for the picture below.
Leokris [45]
228-12.50*2=x*10
228-25=10x
203=10x
Divide both sides by 10 and it is:
20.3=x

The price of each ticket is $20.30

Hope this helps :)
4 0
4 years ago
Bob bought a broken motor scooter, repaired it, and sold the scooter for $130. That was $50 less than 1.5 times what he paid for
FromTheMoon [43]

Answer: $120

Step-by-step explanation:

Assume the original price is x.

He sold the scooter for $130 and this was $50 less than 1.5 times what he paid for it.

Relevant formula is therefore:

1.5x - 50 = 130

1.5x = 130 + 50

x = 180/1.5

x = $120

4 0
3 years ago
I need the answer... PLZ PLZ
andriy [413]

Answer:

Step-by-step explanation:

The answer is a you welcome

8 0
3 years ago
Determine the axis of symmetry for the function f(x) = −4(x + 7)2 − 3.
spayn [35]

Answer:

  x = -7

Step-by-step explanation:

The vertex form of this equation tells us it is a downward-opening parabola with its vertex at (-7, -3). The line of symmetry is the vertical line through the vertex: x = -7.

___

Vertex form is ...

  y = a(x -h) +k

where a is the vertical expansion factor, and (h, k) is the vertex. When a < 0, the parabola opens downward. When a > 0, it opens upward. (When a=0, the "parabola" is a horizontal line at y=k.)

6 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPP I"LLLL GIVE FIVE STAARS AND BRAINLIEST!!!!!!!!!!!!!!!
ollegr [7]

Answer:

c. f(n) = (n+1)^2 + 2

Step-by-step explanation:

It is c. because...

f(n) = (1+1)^2 + 2

        2^2 + 2

        4 + 2 = 6 (first term)

f(n) = (2+1)^2 + 2

        3^2 + 2

        9 + 2 = 11 (second term)

f(n) = (3+1)^2 + 2

        4^2 + 2

        16 + 2 = 18 (third term)

3 0
3 years ago
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