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Flura [38]
2 years ago
15

1252

Mathematics
1 answer:
Slav-nsk [51]2 years ago
8 0
I think it last one 25
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Please helppppp meeeeeee!!!!!!!!!!!!!!!!!!!!
LenKa [72]

Answer:

The option is C i.e 115°, 65°. proof is given below.

Step-by-step explanation:

Given:

ABCD is a quadrilateral.

m∠ A = 100 + 5x

m∠ B = 77 - 4y

m∠ C = 106 + 3x

m∠ D = 47 + 6y

To Prove:

ABCD is a parallelogram if opposing angles are congruent by finding the measures of angles.

m∠ A = m∠ C and

m∠ B = m∠ D

Proof:

ABCD is a quadrilateral and is a parallelogram if opposing angles are congruent.

∴ m∠ A = m∠ C

On substituting the given values we get

∴  100 + 5x  = 106 +3x

∴ 5x-3x=106-100\\\\2x=6\\\\x =\frac{6}{2} \\\\x=3

m∠ A = 100 + 5x = 100 + 5 × 3 =100 + 15 = 115°

m∠ C = 106 + 3x = 106 + 3 ×3 =106 + 9 = 115°

∴  m∠ A = m∠ C = 115°

Similarly,

∴ m∠ B = m∠ D

77 - 4y = 47 + 6y

10y = 77 - 47

10y =30

∴y=\frac{30}{10} \\y = 3\\

m∠ B = 77 - 4y =77 - 4 × 3 = 77 - 12 = 65°

m∠ D = 47 + 6y = 47 + 6 × 3 = 47 + 18 = 65°

∴ m∠ B = m∠ D = 65°

Therefore the option is C i.e 115°, 65°

5 0
3 years ago
What are some steps for the equation 2=z-14
IgorLugansk [536]
Since the opposite operation of addition is subtraction you subtract. So you add 14 both sides and now z is by itself. finally just add 2 and 14 which is 16

5 0
3 years ago
Why would understanding perpendicular and parallel lines be extremely important to someone in construction? Provide an example o
Tems11 [23]

Understanding perpendicular and parallel lines are extremely important, especially in the engineering field when building infrastructures or houses because they need to calculate how they will keep a building stable. For example, bridges we see have a lot of perpendicular and parallel lines, that's because without those the bridge can't hold itself up, it needs support from the metals that are parallel and perpendicular.

hope this helps!!

5 0
2 years ago
Shortern this expression pls​
pogonyaev

Answer:

c =\frac{8}{3}

Step-by-step explanation:

Given

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}

Required

Shorten

We have:

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}

Rationalize

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}

Expand

c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}

c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}

c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{9}

Take positive square roots

c =\frac{4 + \sqrt 7}{3} +  \frac{4 - \sqrt 7}{3}

Take LCM

c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}

Collect like terms

c =\frac{4  + 4+ \sqrt 7 - \sqrt 7}{3}

c =\frac{8}{3}

4 0
3 years ago
Find the value of x<br> A.25<br> B.85<br> C.75<br> D.105
Masteriza [31]

Answer:

The value of x is 75

Step-by-step explanation:

First we need to find the other angle that doesn't have a number in it.

To find the degrees of the other angle we subtract 155 from 180.

180 - 155 = 25

Now we have to find the value of x. Add 80 and 25 together to get 105. A triangle is going to be 180 degrees. Subtract 105 from 180.

180 - 105 = 75

Now we will add 80, 25, and 75 to check our work.

80+25+75 = 180

7 0
3 years ago
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