Answer:
(5x² +7x -26) units²
Step-by-step explanation:

Area of shaded region
= Area of larger rectangle -area of smaller rectangle
Area of larger rectangle
= (3x -4)(2x +2)
= 3x(2x) +3x(2) -4(2x) -4(2) <em>(</em><em>Expand</em><em>)</em>
= 6x² +6x -8x -8
= 6x² -2x -8
Area of smaller rectangle
= (x -6)(x -3)
= x² -3x -6x +18 <em>(</em><em>Expand</em><em>)</em>
= x² -9x +18
Area of shaded region
= 6x² -2x -8 -(x² -9x +18)
= 6x² -2x -8 -x² +9x -18
= 5x² +7x -26
Answer:

Step-by-step explanation:
given

using the property of log
, and if c =
,
, we can rewrite our function as:

now we can easily differentiate:



This is our answer!
Answer:
Is a quadrilateral with one pair of opposite sides parallel
Step-by-step explanation:
Now:
kimberly = k
jordan = k - 102
2 years ago
kimberly = k - 2
jordan = k - 104
k - 2 = 4(k - 104)
k - 2 = 4k - 416
-3k = -414
k = 138
kimberly is 138
jordan is 138 - 102 = 36
k - 102 = 36