Rise over run so it would be 5 over -2.5 ?? I could be wrong:((
What are the options? But I think a good estimate is $700.
Sample Response: The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds
What did you include in your response? Check all that apply.
I Rewrite the quadratic function as a quadratic equation set equal to zero: 0 = –16t2 + 80t + 0.
Use the quadratic formula to solve for the zeros.
Factor to solve for the zeros.
t = 0 and t = 5 seconds.
The object will hit the ground after 5 seconds.
Answer:
3n²+3n-60
Step-by-step explanation:
Area of rectangle= L*W
A=3(n-1)(n+2)
A=3(n²+n-2)
A=3n²+3n-6
54=3n²+3n-6
3n²+3n-6-54=0
3n²+3n-60=0
Answer:
27
Step-by-step explanation:
