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katen-ka-za [31]
3 years ago
6

HELP PLEASE I'll mark you brainliest

Mathematics
2 answers:
kogti [31]3 years ago
8 0

The answer is the first one . A

insens350 [35]3 years ago
6 0
The correct answer is A
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Solve 4 [5 (12+3)-2]-7 PLSSS HELP MEEE
viva [34]

Answer:

285

Step-by-step explanation:

4(5x15-2)-7

4(75-2)-7

4x73-7

292-7

285

3 0
3 years ago
Solve for x: (8x + 15) = 24
Hatshy [7]

Answer:

Step-by-step explanation:

8x + 15 = 24

8x = 9

x = \frac{9}{8}

7 0
3 years ago
Read 2 more answers
Write an equation that represents the line.<br> Use exact numbers.<br> (-2,-1)<br> (4,6)
vazorg [7]

Check the picture below.

to get the equation of any straight line, we simply need two points off of it, so let's use those in the picture

(\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6})~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{(-2)}}} \implies \cfrac{6 -1}{4 +2} \implies \cfrac{ 5 }{ 6 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{5}{6}}(x-\stackrel{x_1}{(-2)})\implies y-1=\cfrac{5}{6}(x+2) \\\\\\ y-1=\cfrac{5}{6}x+\cfrac{5}{3}\implies y=\cfrac{5}{6}x+\cfrac{5}{3}+1\implies y=\cfrac{5}{6}x+\cfrac{8}{3}

6 0
2 years ago
Choose the correct equation type for each system.
pishuonlain [190]

Answer:

first one

Step-by-step explanation:

3 0
3 years ago
ALGEBRA ILL GIVE BRAINLIEST
Anna007 [38]
Due to the lack of information I assume these are fractions so for 5/35 we times it by 21 and 21 by 35 so they have the same denominator so now we got 105/735 and for 21 we get x/735 so now You put 105/735 and divide by 35 so we get back down to 21 for


3/21 for part 1


Now for part 2 again 15 times 20 and 20 times 15 to equal out the denominators so now we have 240/300 and x/300 so now plug 240 into x and divide down by 15 and now we get

16/20 for part 2

LMK if I am wrong I highly doubt it
4 0
3 years ago
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