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2 years ago

ILL MARK U BRAINLIEST!!

Mathematics

2 answers:

frez [133]2 years ago

5 0

Answer: 125 or some thing

Step-by-step explanation:

Lemur [1.5K]2 years ago

3 0

Answer:

125

Step-by-step explanation:

1/4 of 500 (the total number of girls) is 125.

HTH :)

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Each triangle in the net below has a base of 6 centimeters and a height of 8 centimeters. What is the surface area, in square ce

Misha Larkins [42]

The area of a triangle is 1/2 x base x height.

The area of the triangle is 1/2 x 6 x 8 = 24 square cm.

There are 4 identical triangles so 24 x 4 = 96 square cm.

The area of the square base = 6 x 6 = 36 square cm.

Total area = 96 + 36 = 132 square cm.

5 0

2 years ago

Using y=mx+b find the slope for 7) 8x + 3y = −9

malfutka [58]

Answer:

-8/3

Step-by-step explanation:

8x + 3y = - 9

Let's make y the subject of the formula.

y = - 9/3 - 8x/3

Rearrange

y = - 8x/3 - 3

The slope is the coefficient of x which is - 8/3

If you don't understand, please leave a comment

Please gimme brainliest

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2 years ago

Question 10 of 20

Rina8888 [55]

I can’t see planet a and b can you show me what it says

6 0

2 years ago

Pls help i will give brianliest

Blababa [14]

Answer:

b is the answer

Step-by-step explanation:

4 0

2 years ago

Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.

Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

$\displaystyle T_ n = ar^{n-1}$

Where Tₙ is the nth term, a is the initial term, and r is the common ratio.

We are given that the fifth term T₅ = 96 and the eighth term T₈ = 768. In other words:

$\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}$

Substitute and simplify:

$\displaystyle 96 = ar^4 \text{ and } 768 = ar^7$

We can rewrite the second equation as:

$\displaystyle 768 = (ar^4) \cdot r^3$

Substitute:

$\displaystyle 768 = (96) r^3$

Hence:

$\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2$

So, the common ratio r is two.

Using the first equation, we can solve for the initial term:

$\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}$

In conclusion, of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

7 0

2 years ago