Adam went to McDonald's and bought a Big Mac and 2 small fries. Adam spent
1 answer:
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Answer:
The minimum y-value is
or
Step-by-step explanation:
we have
This is the equation of a vertical parabola open up
The vertex is the minimum y-value on the graph
Convert the equation into vertex form
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Factor the leading coefficient
Complete the square. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
------> equation in vertex form
The vertex is the point (-0.5,-7.75)
therefore
The minimum is the point (-0.5,-7.75)
The minimum y-value is
see the attached figure to better understand the problem
The equation p=4+3y is maximised at (4,5) and the maximised value is 31.
Given equation p=4x+3y and constraints x>0,x<4, y<5.
We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.
To find out the points we have to make graphs of the constraints first.
From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).
The above points are common points of graphs of all constraints.
The value of equations are as under:
At (0,0) , p=4*0+3*0=0
At (0,5), p=4*0+3*5=15
At (4,0),p=4*4+3*0=16
At (4,5),p=4*4+3*5=16+15=31
Maximum value of p is 31 and that is for (4,5).
Hence the equation is maximised at (4,5) and the maximum value is 31.
Learn more about equation at brainly.com/question/2972832
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