Quadrant I : cot(x) > 0 → -cot(x) < 0
Quadrant II : cot(x) < 0 → -cot(x) > 0
Quadrant III : cot(x) > 0 → -cot(x) < 0
Quadrant IV : cot(x) < 0 → -cot(x) > 0
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Answer: a)

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign
140 quarts of oil
49 quarts÷7 cars=7 quarts per car
7 quarts×20 cars=140 quarts
Answer:
The marked angle could be named either NPO or OPN
Step-by-step explanation:
The points can be put in any order except the middle point, which has to be put in the middle. Hope that helps!
Answer:
I-
Step-by-step explanation:
) 5)8%2=80)4)<em>88</em><em>=</em><em>5</em><em>=</em><em>5</em><em>=</em><em>88</em><em>=</em><em><u>9</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em><em><u>5</u></em><em><u>=</u></em>
Answer:
Part 1) The algebraic expression is equal to
or 
Part 2) The algebraic expression is equal to 
Step-by-step explanation:
Part 1) we have (n-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

Distributed

Part 2) we have n^(-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)
Remember that

so
