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3 years ago

9. If each of the following pairs represents a pair of equivalent rational

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

7 0

Answer:

-35/6

Step-by-step explanation:

We need to find the value of x , And the given pair of Rational numbers are equal.

Question (I) :-

→ 3/4 = 7/x

→ 7/x = 3/4

→ 1/x = 3/4 × 1/7

→ 1/x = 3/28

→ x = 28/3

Question (ii) :-

→ x/7 = -5/6

→ x = -5/6 × 7

→ x = -35/6

<h3>• Hence the value of x is -35/6 .</h3>

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ANSWER ASAP |What is the measure of angle x?

Marina86 [1]

Answer:

x = 83°

Step-by-step explanation:

41, 56 and the missing angle = 180° ( form a straight angle )

missing angle = 180° - (41 + 56)° = 180° - 97° = 83°

The angle x and the missing angle are vertically opposite and congruent

Hence x = 83°

8 0

3 years ago

8-3x=17 solve for x and check your answer.

nasty-shy [4]

Answer:

x = 3

Step-by-step explanation:

8 - 3x = 17

You have to switch the 8 to the other side. To do this, you would have to move it after the 17 and add a minus to it, making it a -8 (this is because when a number is switched to the other side of the '=' sign, the number gets 'mirrored' aka positive numbers become negative and negative numbers become positive).

3x = 17 - 8

3x = 9

Now you have to do the same thing you did with 8 but instead you have to do it with 3. Since 3 has an invisble 'times sign' by it, the number after the equals will be divided by 3 in this case so...

x = 9 ÷ 3

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4 0

3 years ago

Read 2 more answers

What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?

notsponge [240]

$x^2+bx+c$ will have real roots when the discriminant of the quadratic, $\Delta=b^2-4c$ , is non-negative, i.e.

$b^2-4c\ge0\implies b^2\ge4c$

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking $b,c$ at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both $b,c$ are chosen indepently of one another from [0, 1]. Let $B,C$ denote the random variables that take on the values of $b,c$ , respectively. I'll assume $B,C$ are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

$f_X(x)=\begin{cases}1&\text{for }0$

$F_X(x)=\begin{cases}0&\text{for }x$

where $X$ is either of $B,C$ .

Then the question is to find $P(B^2\ge4C)$ . We have

$P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)$

and we can condition the random variable $C$ on the event of $B=b$ by supposing

$P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)$

then integrate over all possible values of $b$ .

$=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db$

$=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db$

$=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}$

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3 years ago

I WILL MARK THE BRAINLIEST A baker tops each specialty cupcake with a flower that he makes from buttercream frosting. He can mak

wel

Answer:

The answer will be C) 7

5 0

3 years ago

Please need this answer fast it is the last piece to my pie chart for math!!!! A catering service offers 3 appetizers, 5 main co

Brut [27]

To find in how many ways this can be done, we can use the method of combination.

As the customer have to choose 2 out of 3 appetizers, the combination would be 3C2.

For 4 out of 5 main courses, the combination wouls be 5C4.

For 6 out of 8 desserts, the combination would be 8C6.

We can then combine them into a single equation to find the answer:

3C2 x 5C4 x 8C6
=420

Therefore, the answer is 420 ways.

Hope it helps!

7 0

3 years ago