Answer: 
Step-by-step explanation:
Given
Complex number is 
Its conjugate is obtained by changing the sign of the original number i.e. 
The product of the two numbers is
![\Rightarrow (2-i5)(2+i5)=2^2-(5i)^2\quad \quad [(x+y)(x-y)=x^2-y^2]\\\\\Rightarrow (2-i5)(2+i5)=4-25i^2\\\\\Rightarrow (2-i5)(2+i5)=4+25=29](https://tex.z-dn.net/?f=%5CRightarrow%20%282-i5%29%282%2Bi5%29%3D2%5E2-%285i%29%5E2%5Cquad%20%5Cquad%20%5B%28x%2By%29%28x-y%29%3Dx%5E2-y%5E2%5D%5C%5C%5C%5C%5CRightarrow%20%282-i5%29%282%2Bi5%29%3D4-25i%5E2%5C%5C%5C%5C%5CRightarrow%20%282-i5%29%282%2Bi5%29%3D4%2B25%3D29)
Answer:
Not Similer
Step-by-step explanation:
we can use the process of elimination, first AA isn't it because the corresponding angles arn't equal, next SSS itsn't it because we don't know the side lengths, and lastly SAS isn't it because we still don't know the side lengths.
X=-12,0
Y=-0,12 hope this helps:/
(f-g)(x) = 4x²-2x-12 which,evaluated at x=4, gives 64-8-12=44