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3 years ago

PLEASE HELP GEOMETRY

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

$\frac{6}{18+6}= \frac{x}{8 }$

24x=48

x=2

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Find the value of x, circles and angles

lorasvet [3.4K]

Answer:

x = 50

Step-by-step explanation:

When two secants intersect in the interior of a circle, the angles formed are the average of the arc an angle and its vertical intercept. In this case, our angle, 73, should be the average of x and 96. We can translate this to an equation and solve:

$\frac{x+96}{2} = 73$

x + 96 = 146

x = 50

4 0

3 years ago

A carnival charges two different prices for admissions. Adults cost $4 while children cost $1.50. If a total of $5050 was collec

GenaCL600 [577]

Answer:

Step-by-step explanation:

We have to have 2 different equations to solve this. One equation will represent the number of tickets sold while the other represents the money collected when the tickets were sold.

We know that adult tickets + children tickets = 2200 tickets.

That's the "number of tickets" equation. Let's call adult tickets "a" and children's tickets "c". So a + c = 2200

Now if each adult costs $4, then the expression that represents that as a cost is 4a. If there is 1 adult, the cost is $4(1) = $4; if there are 2 adults, the cost is $4(2) = $8; if there are 3 adults, the cost is $4(3) = $12, etc.

The same goes for the children's tickets. If each child's ticket is $1.50, then the expression that represents the cost of a child's ticket is 1.5c (we don't need the 0 at the end; it doesn't change anything to drop it off). The total money brought in from the cost of these tickets was $5050, so

4a + 1.5c = 5050

Let's solve the first equation for a. If a + c = 2200, then a = 2200 - c. Sub that into the second equation and solve it for c:

4(2200 - c) + 1.5c = 5050 and

8800 - 4c + 1.5c = 5050 and

-2.5c = -3750 so

c = 1500

That means that there were 1500 children's tickets sold. If a + c = 2200, then a + 1500 = 2200 so

a = 2200 - 1500 so

a = 700

There were 1500 children's tickets sold and 700 adult tickets sold.

7 0

3 years ago

Thomas Vega offers to pay $59 of the March cell phone bill. Each of the other 4 members of the family agrees to split the rest o

bija089 [108]

59×2=118 cost of bill.
59÷4=14.75 for the other 4 if the bill was 118 assuming Thomas pays half.

or...59 ×5=295
assuming they all pd 1/5 of the bill

6 0

3 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

5 0

3 years ago

It says to find the area of the figure but I have no idea what to do

Westkost [7]

2.5 is also on the top and try multiplying 2.5 and 10

6 0

3 years ago