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NNADVOKAT [17]
3 years ago
13

PLEASE HELP GEOMETRY

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

\frac{6}{18+6}= \frac{x}{8 }

24x=48

x=2

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Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no
erastova [34]
1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96 
$96 + $68 = $164     So Shally has $164

Now, $288 - $96 = $192.    So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96
 

4 0
3 years ago
Write the equation of a line with a slope of -2 and a y-intercept of 5:
saveliy_v [14]
Answer: y = -2x +5 , so C (you probably just forgot to put the x)

Explanation: y = mx+b m represents the slope, b represents the y intercept
6 0
3 years ago
Read 2 more answers
In ΔCDE, \overline{CE}
abruzzese [7]

Answer:

m\angle CDE=14^o

Step-by-step explanation:

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

see the attached figure to better understand the problem

so

∠DEF=∠ECD+∠CDE

substitute the given values

(4x+5)^o=(x+9)^o+(x+8)^o

solve for x

Combine like terms

(4x+5)^o=(2x+17)^o

Group terms

4x-2x=17-5

2x=12

x=6

Find the measure of angle CDE

m\angle CDE=(x+8)^o

substitute the value of x

m\angle CDE=(6+8)=14^o

8 0
3 years ago
3. Han has a fish tank that has a length of 14 inches and a width of 7 inches. Han puts in
muminat
The height of the tank is 12 inches
4 0
2 years ago
Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. What is the volume of the display box? Explain your
Black_prince [1.1K]

Answer:

\text{Volume of display box}=216\text{ in}^3    

Step-by-step explanation:

We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.

We know that the box is in form of cuboid, so its volume would be length times width times height.

\text{Volume of display box}=6\text{ in}\times 9\text{ in}\times 4\text{ in}

\text{Volume of display box}=216\text{ in}^3

Therefore, the volume of the display box is 216 cubic inches.

7 0
2 years ago
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