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3 years ago

!!Help!! i will give brainliest

Mathematics

2 answers:

Tems11 [23]3 years ago

6 0

Answer:

94m^2

89.1mm^2

Step-by-step explanation:

Roman55 [17]3 years ago

3 0

Answer:

Figure 1 = 94m^2

Figure 2 = 89.1

Step-by-step explanation:

Figure 1:

Break the figure into pieces and then add. 24 + 30 + 40 = 94

Figure 2:

8 * 8 = 64

then using C = 2 pi r you get 25.13

64 + 25.13 = 89.13

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PLEASE HELP ASAP 30 PTS AND BRAINLIEST

mart [117]

Answer:

The answer is 8x3=24

Step-by-step explanation:

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3 years ago

What is the mean ? -4 9 -8 0 10 1 4 3 0 -5

Genrish500 [490]

I think it’s 3 because

8 0

3 years ago

Cory has 24packages of sunflower seeds. If each package has 15 seeds, how many sunflower seeds does he have altogether?

zepelin [54]

24*15 =360
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4 0

4 years ago

Write in standard form. (x+1)(x+1)(x+2)

german

Answer:

x^3 + 4x^2 + 5x + 2.

Step-by-step explanation:

(x+1)(x+1)(x+2) = (x^2 + x + x + 1)(x + 2) = (x^2 + 2x + 1)(x + 2) = x^3 + 2x^2 + 2x^2 + 4x + x + 2 = x^3 + 4x^2 + 5x + 2.

Hope this helps!

4 0

3 years ago

A botanist wishes to estimate the mean number of seeds for a certain fruit. She samples 11 specimens and finds the average numbe

Aliun [14]

Answer:

a)The 98% of confidence intervals are

Lower bound of CI = 47 -3.82436 = 43.1756

Upper bound of CI = 47 + 3.82436 = 50.8243

b) The conditions are required for the validity of the interval

A) μ known

Step-by-step explanation:

Explanation:-

The given sample size is 'n' =11

Given the average number of seeds is 47 with a standard deviation of 7

Sample mean (x⁻) = 47

Standard deviation (S) = 7

The 98% of confidence intervals are

$(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )$

$(47 - t_{0.02} \frac{7}{\sqrt{11} } , 47+ t_{0.02}\frac{7}{\sqrt{11} } )$

The degrees of freedom = n-1 =11-1 =10

t₀.₀₂= 1.812 ( from t - table)

now the intervals are

$(47 - 1.812 \frac{7}{\sqrt{11} } , 47+ 1.812\frac{7}{\sqrt{11} } )$

Lower bound of CI = 47 -3.82436 = 43.1756

Upper bound of CI = 47 + 3.82436 = 50.8243

The conditions are required for the validity of the interval

A) μ known

Explanation:-

If a random sample xi of size 'n' has been drawn from a normal population with a specified mean (μ) known.

The limit for (μ) is given by

$(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )$

5 0

3 years ago