The percentage of the radioactive isotope left is 25.0000%.
<h3>What is the half life?</h3>
The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.
Now;
We are told that;
Half life (t1/2) = 55 days
Time taken (t) = 115 days
Ratio of isotope remaining = N/No
Thus;
N/No = (1/2)^t/t1/2
N/No = (1/2)^115/55
N/No = (1/2)^2
N/No =1/4
Hence, the percentage = 1/4 * 100/1 = 25.0000%
Learn more about half life of an isotope:brainly.com/question/16387602
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First take triangle BDH. We know B is 46 degrees and D is 33 degrees. Since the angles of a triangle equal 180 we get
180 - 46 - 33 = 101 for H.
H is supplementary to x, so their sum is also 180. This gives 180 - 101 = 79.
So x is 79 degrees.
Answer: 0.6 in 10 % ; 0.4 in 15 %
Step-by-step explanation:
1. (x*10%) + (y*15%)/ x+y=12%
2. x+y = 1 x= 1-y
(0.1x + 0.15y/ x+y= 12/100) * 100
(10x + 15y/x+y = 12)*(x+y)
10x+15y= 12x + 12y
-2x=-3y
2x = 3y 2(1 - y)= 3y
2-2y=3y 2= 5y
y= 0.4
x= 0.6
slope intercept form is just solve for y
y+16=3(x-0)
y+16=3(x)
y+16=3x
mius 16 both sides
y=3x-16
3rd option
