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Levart [38]
3 years ago
6

Which rules define the function graphed below? (15 points cuz I'm stumped)

Mathematics
1 answer:
Lana71 [14]3 years ago
4 0

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that x \le 0 but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when x \ge 0

So we could have this piecewise function

f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}

Or we could easily swap the "or equal to" portion to move to the first part instead like this

f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}

Either way, we're involving the equations mentioned in choice A

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How to find third coordinate when given midpoint and a point?
IgorLugansk [536]
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u have an endpoint at (6,5)......ad the midpoint is (4,2)....find the other endpoint.

midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
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other endpoint (x,y)...x2 = x and y2 = y
sub into the formula
m = (6 + x) / 2, (5 + y) / 2

okay, so the midpoint is (4,2)....so ur x value will equal 4
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midpoint is (4,2)....so the y value will equal 2
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