Answer:
False 8^0 is not greater than 8^1
Step-by-step explanation:
8^0 = 1
8^1= 8
8>1
A. 2/5
B.2/5
C. The slope of ABC and AGH are equal
The factorial ! just means we multiply by every natural number less that the value so
6! =6×5×4×3×2×1= 720
for permutations we use the formula n!/(n-r)!
so we have 8!/(8-5)!=8!/3!=8×7×6×5×4
for combinations s we have n!/(n-r)!r!
so we have 12!/(12-4)!4!=12!/8!4!=12×11×10×9/4×3×2=11×10×9/2=99×5
Hey DatGamer13!
Question:
Solve for x
Solution:
Subtract 10 from both sides.
3x^2 + 13x − 10 = 10 − 10
3x^2 + 13x − 10 = 0
Factor left side of equation.
(3x − 2) (x + 5) = 0
Set factors equal to 0.
3x − 2 = 0 or x + 5 = 0
Answer:
x = 2/3 or x = −5
