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kari74 [83]
3 years ago
12

Billy is playing a game using a bag with 11 marbles inside. The bag contains 3 red, 3 orange, 1 yellow, 2 purple marbles, and 2

Pink. Each time he picks an orange marble, she will win a prize. If he picks a marble twice, WITHOUT replacement, what is the probability he will win a prize on both picks? 5/110 5/21 3/55 9/121
Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer: 3/55

Step-by-step explanation:

From the information given, the bag contains 3 red, 3 orange, 1 yellow, 2 purple marbles, and 2 Pink marbles. Each time he picks an orange marble, she will win a prize.

If he picks a marble the first time, the probability of picking an orange marble will be 3/11. After that we will have 10 marbles left as one has been picked and have 2 orange marbles left, then the probability of picking another orange marble will be 2/10.

Therefore, the probability he will win a prize on both picks will be:

= 3/11 × 2/10

= 6/110

= 3/55

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Solve by taking the square root: (x-1)^2=9<br> Step by step PLEASE HELP!!!
Solnce55 [7]

Answer: \\  {(x -1 )}^{2}  = 9 \\ \Leftrightarrow  \sqrt{ {(x - 1)}^{2} }  =  \sqrt{9}   \\ \Leftrightarrow  |x - 1|  = 3 \\ \Leftrightarrow x - 1 =  \pm3 \\ \Leftrightarrow x =  - 2 \:  \vee \: x = 4

8 0
3 years ago
What is the exact circumference of a circle with a diameter of 40 feet?
Irina-Kira [14]

Answer:

The answer is

<h2>126 feet</h2>

Step-by-step explanation:

Circumference of a circle is πd

Where d is the diameter

From the question

d = 40 feet

Circumference of the circle is

40π

= 125.66

= 126 feet to the nearest whole number

Hope this helps you

7 0
4 years ago
Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report
Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M±\frac{t*s}{\sqrt{N}} where

  • M is the average track length (12 μm) in the report
  • t is the two tailed t-score in 99% confidence interval (2.977)
  • s is the standard deviation of track lengths in the report (2 μm)
  • N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12±\frac{2.977*2}{\sqrt{15}} =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0
3 years ago
Complete the factoring<br> 7y+42=7()
stiks02 [169]
7y + 42 = 7(y + 6)

Hope this helps.
3 0
3 years ago
Read 2 more answers
For employees at a large company, the mean number of overtime hours worked each week is 9.2 hours with a population standard dev
topjm [15]

Answer:

z=\frac{9.3-9.2}{\frac{1.6}{\sqrt{49}}}= 0.4375

And we can use the normal table and the complement rule we got:

P(z>0.4375)= 1-P(z

Step-by-step explanation:

For this case we have the following parameters given:

\mu = 9.2 , \sigma =1.6

We select a ample size of n=49. And we want to find this probability:

P(\bar X> 9.3)

And for this case is a right tail probability and we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z=\frac{9.3-9.2}{\frac{1.6}{\sqrt{49}}}= 0.4375

And we can use the normal table and the complement rule we got:

P(z>0.4375)= 1-P(z

8 0
3 years ago
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