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svlad2 [7]
3 years ago
12

Rewrite in simplest terms. 4 (-6g - 10h) + 3h - 4 (- 3h - 10g)

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer: 16g - 25h

4 (-6g - 10h) + 3h - 4 (- 3h - 10g)

-24g - 40h +3h +12h +40g

16g - 25h

Step-by-step explanation:

if this is wrong im sorry

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Do all rational functions have vertical asymptotes
Tpy6a [65]
A given rational function may or may not have a vertical asymptote (depending upon whether the denominator ever equals zero), but (at this level of study) it will always have either a horizontal or else a slant asymptote.
4 0
3 years ago
Find the value of 10! / (10-2) !
Gnesinka [82]

Answer:

90

Step-by-step explanation:

10! / (10 - 2)!

=10!/8!

=10 * 9 * 8! /8!

=90 * 8!/8!

90

Hope this helps. Please mark as brainliest if possible. Have a nice day

3 0
3 years ago
Solve (x+5)+4=16 by first subtracting 4 and then 5. Show your work and justify each step.
Vinil7 [7]
(x+5)+4=16\ \ \ subtract\ 4 \ and \ 5 \ to\ both\ sides \\\\x+5+4-5-4=16-4-5 \\\\x=7


3 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
What is the measure of ∠HFG?<br> (See attachment)
madam [21]
92 degrees

Triangle= 180 degrees
180-60-28= 92

:)
7 0
3 years ago
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