1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elina [12.6K]
3 years ago
8

Rewrite as a simplified fraction. 2.267....=?

Mathematics
2 answers:
Ugo [173]3 years ago
8 0

Answer:

2267/1000

Step-by-step explanation:

fiasKO [112]3 years ago
6 0
The simplified fraction of 2.267 = 2267/1000
You might be interested in
A bus rental company charges $60 for booking a bus and $120 for each hour the bus is rented. A tour group pays $780 to rent a bu
Rom4ik [11]

Answer:

B

Step-by-step explanation:

Its really pretty easy.

5 0
3 years ago
Cole has a can of marbles. NEED HELP It would mean so much to me.
Strike441 [17]

Answer:

C

plz can i get brainliest

7 0
3 years ago
Grade 5 farm has 85 rows of cabbages.If there are 58 cabbages in each row ,how many cabbages are there in the farm to the neares
ElenaW [278]

The number of cabbages on the farm to the nearest thousand is 5000 based on the given parameters

<h3>How to determine the number of cabbages on the farm to the nearest thousand</h3>

The number of rows is given as:

Number of rows = 85

The number of cabbage on each row is

Number of Cabbage on each row = 58

The number of cabbages on the farm is calculated as:

Farm = Number of rows * Number of Cabbage on each row

Substitute the known values (i.e. Number of rows = 85 and Number of Cabbage on each row = 58) in the above equation

Farm = 85 * 58

Evaluate the product of 85 and 58

Farm = 4930

Approximate the above result (i.e. 4930) to the nearest thousand

Farm = 5000

Based on the given parameters, the number of cabbages on the farm to the nearest thousand is 5000

So, the complete parameters are:

Number of rows = 85

Number of Cabbage on each row = 58

Number of Cabbage in the farm = 5000

Read more about products at:

brainly.com/question/10873737

#SPJ1

4 0
2 years ago
A toy store purchases Jedi lightsabers from the manufacturer for $18. The manager decides to mark up the price by of the origina
TEA [102]

Answer:

hehe

Step-by-step explanation:

4 0
3 years ago
An aircraft seam requires 24 rivets. The seam will have to be reworked if any of these rivets are defective. Suppose rivets are
kirill [66]

Answer:

Step-by-step explanation:

a)

p(d) - probability of a rivet being defective

p(r) - probability of seam needing to be reworked

The probability of the seem needing to be reworked is equal to the probability that ANY of 24 rivets is defective

Thus the probability that none of the 25 rivets is defective is 1-p(r)

p(r) = 16%, thus 1-p(r) = 84%

1-p(r) = (1-p(d))^24

0.84 = (1-p(d))^24

0.84^(1/24) = 1-p(d)

==> 1-p(d) = 0.9927615998

==> p(d) = 1-0.9927

==> p(d) = 0.0073

b) given p(r) = 8%, thus 1-p(r) = 92%

1-p(r) = (1-p(d))^24

0.92 = (1-p(d))^24

0.92^(1/24) = 1-p(d)

==> 1-p(d) = 0.99653179446

==> p(d) = 1-0.9965

==> p(d) = 0.0035

5 0
3 years ago
Other questions:
  • What is the coefficient of the x^2 term of the algebraic expression 2x^4+x^2-x+7
    15·2 answers
  • Does any one know all the blanks?
    8·1 answer
  • !!!PLEASE HELP ME !!! AND INCLUDE AN EXPLANATION
    10·1 answer
  • I am part of a whole I am greater than three fourths but less than nine tenths I am a decimal with a 3 in my hundredths place wh
    15·1 answer
  • The medians of a right triangle that are drawn from the vertices if the acute angles have lengths of 2 square root 13 and square
    5·1 answer
  • Stuck!!! Pleaseeeeee helpp
    5·1 answer
  • The perimiter of a rectangle is 128 inches. The width of the rectangle is 4y inches. Find the length of the rectangle in terms o
    15·1 answer
  • Help!!!
    9·1 answer
  • 4p - 3=17<br> Please help
    7·2 answers
  • Why can you not do negative numbers to the power of 1. 5?.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!