Your answer will be,
ANSWER: (4b - 5)^2
You're welcome :)
I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
<span>x= -13 <span>± √169 + 192 / 4</span>
x= -13 </span>± √<span>361 / 4
The square root of 361 is 19.
So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2
x = -8, 3/2</span>
They do not intersect, they are parallel lines.
Answer:
Step-by-step explanation:
function
Answer:
The function f(x) = -9.5 + 6 + x² is neither odd or even.
Step-by-step explanation:
We know that a function is termed as 'even' when
f(-x) = f(x) for all x
We know that a function is termed as 'odd' when
f(-x) = -f(x) for all x
Given the function
f(x) = -9.5x⁵ + 6 + x²
substitute x with -x
f(-x) = -9.5(-x)⁵ + 6 + (-x)²
as (-x)⁵ = -x⁵, so
f(-x) = -(-9.5x)⁵ + 6 + (-x)²
Apply exponent rule: (-a)ⁿ = aⁿ, if n is even
f(-x) = -(-9.5x)⁵ + 6 + x²
Apply rule: -(-a) = a
f(-x) = 9x⁵ + 6 + x²
As
f(-x) ≠ f(x) ≠ -f(x)
Therefore, the function f(x) = -9.5 + 6 + x² is neither odd or even.
