Answer:
9.11*10^-4 %
Step-by-step explanation:
To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.
For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320
In order to find the total amount of ways to place the rooks, you can just use a combinatoric:
![\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D64%5C%5C8%5Cend%7Barray%7D%5Cright%5D%3D%20%5Cfrac%7B64%21%7D%7B8%21%2864-8%29%21%7D%20%3D%204.43%2A10%5E9)
Then:
P = 
Would it be (-3)^7? (-2187)
Answer:
7/15x - 9
Step-by-step explanation:
(4/5x - 5) - (1/3x + 4)
remove the parentheses
4/5x - 5 - 1/3x - 4
simplify each variable
4/5x - 9 - 1/3x
7/15x - 9
Answer:
14
Step-by-step explanation:
The least common multiple is a number that both numbers can multiply something to get to, and the smallest possible common one.
Let's try listing out the multiples of 2:
2, 4, 6, 8, 10, 12, 14, 16, 18, 20
And the multiples of 7:
7, 14, 21, 28, 35, 42, 49, 56, 63, 70
Notice that both have the number 14 in common, and it is the first number that they do so. There are lots of other multiples that they have in common too, but 14 is the least.
Answer: 129
Step-by-step explanation:
It is 129 because y is less than 70 so the greatest possible value for that is 69 and z is less than or equal to 60 so 69 + 60 =129
