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VLD [36.1K]
3 years ago
5

ASAP BRAINLIEST

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

See answers below with explanations

Step-by-step explanation:

<u />

<u>Problem 1:</u>

One number is 10 less than twice another.

This translates to n=2m-10

Their difference is 31

This translates to n-m=31

n-m=31

(2m-10)-m=31

m-10=31

m=41

n-41=31

n=72

Therefore the larger number is (B) 72

<u>Problem 2:</u>

Use elimination:

 2x + y = 7

<u>- 2x -3y = -1</u>

       4y = 8

         y = 2

2x+2=7

2x=5

x=2.5

Therefore the solution is (A) {(2.5,2)}

<u>Problem 3:</u>

Use elimination:

  x - y = 1

<u>-  x + y = -1</u>

      -2y = 2

Check if each answer eliminates to -2y=2:

2x - 3y = 6

<u>4x +  y = 4</u>

-2x - 4y = 2 NO

4x - 3y = 6

<u>4x -   y = -4</u>

    -2y = 10 NO

4x + 3y = -6

<u>4x -   y =  4</u>

      4y = -10 NO

Neither answer is correct

<u>Problem 4:</u>

No visible items to match

<u>Problem 5:</u>

2(2x - y = -2)

4x - 2y = -4

x + 5y = 3

<u>4x - 2y = -4</u>

5x + 3y = -1

None of the answer choices are correct

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3 years ago
A biologist recorded a count of 348 bacteria present in a culture after 5 minutes and 1088 bacteria present after 20 minutes. To
Nat2105 [25]

Answer:

The initial bacteria population is 238

Step-by-step explanation:

Let us have the increase as an exponential equation

P(t) = I(1 + r)^t

where P(t) is the count at a particular time

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t is the time

So for 5 minutes, we have

348 = I(1 + r)^5

For 20 minutes

1088 = I(1 + r)^20

Divide the second equation by the first

1088/348 = I(1 + r)^20/I(1 + r)^5

3.13 = (1 + r)^15

Take the ln of both sides

ln 3.13 = 15 ln (1 + r)

ln 3.13/15 = ln (1 + r)

0.0761 = ln (1 + r)

1 + r = e^0.0761

1 + r = 1.079

r = 1.079-1

r = 0.079 which is 7.9%

So per minute. we have an increase of 7.9%

So let’s get I by substituting

From;

348 = I(1 + 0.079)^5

348/1.079^5 = I

I = 237.9 which is 238 to the nearest whole number

4 0
3 years ago
Dividing polynomials simplify 10c+6÷2
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Answer: 5c+3

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4 years ago
What is the solution to the equation?
mojhsa [17]
D. x=<span>−<span>4
Why?
</span></span>Let's solve your equation step-by-step.
<span><span>2<span>(<span>x−7</span>)</span></span>=<span><span>10x</span>+18
</span></span>Simplify both sides of the equation.
<span><span>2<span>(<span>x−7</span>)</span></span>=<span><span>10x</span>+18
</span></span><span>Simplify:
</span><span><span><span>2x</span>−14</span>=<span><span>10x</span>+18
</span></span>Subtract 10x from both sides.
<span><span><span><span>2x</span>−14</span>−<span>10x</span></span>=<span><span><span>10x</span>+18</span>−<span>10x
</span></span></span><span><span><span>−<span>8x</span></span>−14</span>=18
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Read 2 more answers
Find the nth term of the sequence 7,25,51,85,127​
olya-2409 [2.1K]

Let <em>a </em>(<em>n</em>) denote the <em>n</em>-th term of the given sequence.

Check the forward differences, and denote the <em>n</em>-th difference by <em>b </em>(<em>n</em>). That is,

<em>b </em>(<em>n</em>) = <em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>)

These so-called first differences are

<em>b</em> (1) = <em>a</em> (2) - <em>a</em> (1) = 25 - 7 = 18

<em>b</em> (2) = <em>a</em> (3) - <em>a</em> (2) = 51 - 25 = 26

<em>b </em>(3) = <em>a</em> (4) - <em>a</em> (3) = 85 - 51 = 34

<em>b</em> (4) = <em>a </em>(5) - <em>a</em> (4) = 127 - 85 = 42

Now consider this sequence of differences,

18, 26, 34, 42, …

and notice that the difference between consecutive terms in this sequence <em>b</em> is 8:

26 - 18 = 8

34 - 26 = 8

42 - 34 = 8

and so on. This means <em>b</em> is an arithmetic sequence, and in particular follows the rule

<em>b</em> (<em>n</em>) = 18 + 8 (<em>n</em> - 1) = 8<em>n</em> + 10

for <em>n</em> ≥ 1.

So we have

<em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>) = 8<em>n</em> + 10

or, replacing <em>n</em> + 1 with <em>n</em>,

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8 (<em>n</em> - 1) + 10

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8<em>n</em> + 2

We can solve for <em>a</em> (<em>n</em>) by iteratively substituting:

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 2) + 8 (<em>n</em> - 1) + 2] + 8<em>n</em> + 2

<em>a</em> (<em>n</em>) = <em>a </em>(<em>n</em> - 2) + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 3) + 8 (<em>n</em> - 2) + 2] + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 3) + 8 (<em>n</em> + (<em>n</em> - 1) + (<em>n</em> - 2)) + 3×2

and so on. The pattern should be clear; we end up with

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 8 (<em>n</em> + (<em>n</em> - 1) + … + 3 + 2) + (<em>n</em> - 1)×2

The middle group is the sum,

\displaystyle 8\sum_{k=2}^nk=8\sum_{k=1}^nk-8=\frac{8n(n+1)}2-8=4n^2+4n-8

so that

<em>a</em> (<em>n</em>) = <em>a</em> (1) + (4<em>n</em> ² + 4<em>n</em> - 8) + 2 (<em>n</em> - 1)

<em>a</em> (<em>n</em>) = 4<em>n</em> ² + 6<em>n</em> - 3

4 0
3 years ago
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