have you figured out the answer i need help on the problem to
Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)
But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2
Now we can place it in slope point and also in standard form of a line.
Y-y1 = m(X -X1)
Y - -1/2 = -3/2(X - 3/2)
Y + 1/2 = -3/2(X - 3/2)
This is in slope point form.
Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7
6x + 4y = 7
This is in standard form. If you have any questions of the steps just ask.
4x + 2x< 5x-13
solve
6x < 5x-13
subtract 5x
x< (-13)
Answer:
x =120
60,60,120,120
Step-by-step explanation:
The sum of the angles is 360
x + x+ 1/2x + 1/2x = 360
Combine like terms
3x = 360
Divide each side by 3
3x/3 =360/3
x =120
The 4 angles are 120, 120,60,60
From least to greatest
60,60,120,120
